how do i find the absolute and relative uncertainty of my data? Run123Initial Burette Reading (mL) Absolute Uncertainty (mL)0.020.020.0239.9924.9839.8Average Volume EDTA titrated (ml):21.77Final Burette Reading (mL)18.253.1121.69Absolute Uncertainty (ml)Absolute Uncertainty (mL) Total Volume EDTA Titrated (mL) Absolute Uncertainty (mL)21.740.020.020.02% Relative Uncertainty21.8721.690.040.040.04only average the total volumes within 0.1 mL

relative uncertainty as a percentage = (absolute uncertainty/measured value) * 100. absolute…

Run 1 2 3 Initial Burette Reading (mL) Absolute Uncertainty (ml) Final Burette Reading (mL) Absolute Uncertainty (mL) Total Volume EDTA Titrated (mL) Absolute Uncertainty (mL 0.02 21.74 0.02 0.02 0.02 21.87 21.69 0.02 0.02 39.99 24.98 39.8 verage Volume EDTA titrated (ml): 21.77 18.25 3.11 21.69 Absolute Uncertainty (ml) % Relative Uncertainty 0.04 0.04 0.04 only average the total volumes within 0.1 ml

Run 1 2 3 Initial Burette Reading (mL) Absolute Uncertainty (ml) Final Burette Reading (mL) Absolute Uncertainty (mL) Total Volume EDTA Titrated (mL) Absolute Uncertainty (mL 0.02 21.74 0.02 0.02 0.02 21.87 21.69 0.02 0.02 39.99 24.98 39.8 verage Volume EDTA titrated (ml): 21.77 18.25 3.11 21.69 Absolute Uncertainty (ml) % Relative Uncertainty 0.04 0.04 0.04 only average the total volumes within 0.1 ml

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter6: Random Errors In Chemical Analysis

Section: Chapter Questions

Problem 6.15QAP

See similar textbooks

Similar questions

Example 2: You prepared a 0.250 M NH3 solution by diluting 8.45 (±0.04) mL of 28.0 (±0.5) wt% NH3 [density = 0.899 (±0.003) g/mL] up to 500.0 (±0.2) mL. Find the uncertainty in 0.250 M. The molecular mass of NH3, 17.0306 g/mol, has negligible uncertainty relative to other uncertainties in this problem. %3D
The amount of ascorbic acid in cashew juice of different brands was determined by two different methods, colorimetry and titrometry. The results obtained for the two methods for analyzing the different cashew juice are necessary in the following table. Sample Colorimetry (mg/100g) Titrometry (mg/100g) juice brand A 152,2 153,7 juice brand B 150,7 150,7 juice brand C 18,7 18,7 juice brand D 67,4 67,4 Can the two methods be used, indistinctly, to determine ascorbic acid in cashew juice, at a 95% confidence level? Explain.
8) Two different analytical methods are compared for determining Ca. The following are two sets of data. Set 1 Set 2 155.779 155.784 155.787 155.787 155.813 155.765 155.781 155.793 i. i. Determine the mean and the standard deviation in Set 1. Calculate the 95% confidence limit for data in Set 1. Identify a possible outlier in Set 2. Use the Q-test to determine whether it can be retained or rejected at 95% confidence level. ii.
Suppose that you used smaller volumetric apparatus to prepare 0.250 M NH3 solution by diluting 84.6 (±0.8) µL of 28.0 (±0.5) wt% NH3 up to 5.00 (±0.02) mL. Find the uncertainty in 0.250 M.
A titrimetric method for the determination of calcium in limestone was tested by analysis of an NIST limestone containing 30.15% CaO. The mean result of four analyses was 30.26% CaO, with a standard deviation of 0.085%. By pooling data from several analyses, it was established that s   = 0.094% CaO.a. Do the data indicate the presence of a systematic error at the 95% confidence level?b. Do the data indicate the presence of systematic error at the 95% confidence level if no pooled value for s was available?
part A:> to Calculate Concentzahion, use M,V, = M2V2 AB1 - 0.025 M X 2.5 ml = ax 5 ml %3D 0.0125 M 0.01 M x 2. S ml= 5°-]x Ŝ ml [s2] = 0.008 M 0. 002 M 11 2 a - X = 0. 01 M Sohtion a 9- X timels) 9-X ABI 0-0125 0-0025 0.01 0. 223 84.8 0.016구 0.0016구 0.015 0.10 구 니1.2 AB 2 0.0 S16 19.5 O.02 0. 00 1 0. 이19 AB 3 0. 0164 0.0816 28.5 0.이구8 0. 0014 AB 니 0. 0022 0.011 구 0.172 60 AB § 0.이139 0.270 95.2 O. ol14 0.0027 0.008구 A8 6 0. 389 14 5.5 0.0096 0.0031 0.0065 AB구
Practice: uncertainty and relative uncertainty You prepared a 0.250M NH3 solution by diluting 8.45 (+±0.04)mL of 28.0 (±0.5)wt% NH3 (density = 0.899 ± 0.003)g/mL) up to %3D 500.0 (±0.2)mL. Find the uncertainty in 0.250 M. Consider the molar mass of NH3, 17.031g/mol, to have negligible uncertainty. hp
What is a 99% confidence interval uncertainty of the slope when we are given a trendline with a slope of 42.211 and an R² value of 0.9991 for a set of 145 data points?
(a) For use in an iodine titration, you prepare a solution from 0.222 2 (+0.000 2) g of KIO3 [FM 214.001 0 (+0.000 9)] in 50.00 (+0.05) mL. Find the molarity and its uncertainty with an appropriate number of significant figures. (b) Would your answer be affected significantly if the reagent were only 99.9% pure?
Ine density Calculate the molarity of solution prepared by weighing 6.34 g of NaOH using a balance with a standard deviation of ± 0.05 g and dissolving it in a 500 mL of water in a volumetric flask with a standard deviation of ± 0.2 mL.
Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
In a volumetric determination of an analyte A, the data obtained and their standard deviations are as follows: Initial buret reading 0.19 mL 0.02 mL Final buret reading 7.86 mL 0.03 mL Sample mass 63.0 mg 0.2 mg From the data, find the coefficient of variation of the final result for the %A that is obtained by using the equation that follows and assuming there is no uncertainty in the equivalent mass. %A= titrant volume x equivalent mass x 100 %/ sample mass Coefficient of variation = Submit Answer % Try Another Version 10 item attempts remaining