Rewrite the following pseudocode segment using a loop structure in KOTLIN k = (j +15) / 27 loop: if k > 10 then goto out k=k+1 i=3*k-2 goto loop out: . .
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Rewrite the following pseudocode segment using a loop structure in KOTLIN
k = (j +15) / 27
loop:
if k > 10 then goto out k=k+1
i=3*k-2
goto loop
out: . . .
Step by step
Solved in 2 steps
- 1. Rewrite the program segment that follows, using a for loop and do-while loop: = 1; product i = 0; %3D while (i < n) { scanf(“%d", &a); if (a != i) %3D product *= a; ++i; }Nesting Loops Summary In this lab, you add nested loops to a Java program provided. The program should print the letter E. The letter E is printed using asterisks, three across and five down. Note that this program uses System.out.print("*"); to print an asterisk without a new line. Instructions Write the nested loops to control the number of rows and the number of columns that make up the letter E. In the loop body, use a nested if statement to decide when to print an asterisk and when to print a space. The output statements have been written, but you must decide when and where to use them. Execute the program. Observe your output. Modify the program to change the number of rows from five to seven and the number of columns from three to five. What does the letter E look like now?Complete the following sentence. There are two basic forms of loop constructs: while loops and loops.
- Consider the following for loop. int j, s;s = 0;for (j = 1; j <= 10; j++)s = s + j * (j - 1);In this for loop, identify the loop control variable, the initialization statement, loop condition, the update statement, and the statement that updates the value of s.Question 01: Write a program in to display the pattern using a Nested for loops. C -C P-C rP-C orP-C gorp-C rgorp-C argorp-C margorP-C mmargorP-C emmargorP-C remmargorP-C sremmargorP-Cplease solve this Given the following code segment with the enhanced for loop: int [] numbers = {6, 8, 9, 5}; for (int val : numbers) System.out.print(val + “ “); Rewrite the above as a syntactically correct regular for loop statement that gives the same output. Use a loop control variable named i and the printf statement instead of print statement.
- Looping Construct with Floating Point Numbers Write a program that utilizes a while-loop to read a set of five floating-point values from user input. Include code to prevent an endless loop. Ask the user to enter the values, then print the following data: Total Average Maximum Minimum Interest on total at 20% Answer:Help needed ASAP! Language: JAVA Here is a for loop; write the equivalent do-while loop. for( int i = 10; i > 5; i--) System.out.println("Hello");Python Coding-While Loops (In PyCharm Community edition) Create a while loop that SUMS up ALL the numbers given from an initial number and an ending number. Example would be : Input1 : What is the first number? 0 Input2 : What is the last number? 3 DO NOT SHOW but these are the computations inside the code : 0 + 1 + 2 + 3 = 6 This is the Output : The sum of all the number from 0 to 3, is 6 In the code you are going to use a total variable and add each additional time it runs through the loop to that total. REMEMBER the assignment from the first unit of programming where we used this formula : BUT you are going to create your own method using a while loop to emulate what formula accomplishes WITHOUT using this formula. The user will put in the first number and the last to be SUMMED - you will use the while loop to calculate all of the additions leading to the final number.
- NOT using C++ code format Write a pseudocode for the real percentage-to-numerical-grade-equivalent displaying. Only one percentage score can be entered at a time. The grading scale is as follows: example link: (pls follow this one) https://www.code4example.com/pseudocode/pseudocode-examples/2. Find the execution time of the nested 'for' loop given below. #include using namespace std; int main() { int x = 20,sum=0; for(int i=x;i>=0;i--X for(int j=i-1;j>=0;j--X sum = sum+j; } } cout<Q/Rewrite the following loops as for loops. a- int m = 10; do { cout 0) { if (n == 2) break; cout << n<< " } cout << "End of Loop.";SEE MORE QUESTIONS