Rewrite only the lines of code that need to be changed so that the above function converts a postfix expression to a prefix expression.

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 6PE
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7. The following function converts a postfix expression to an infix expression assuming the
expression can only contain unsigned integer numbers and +' and -' operators.
1. public static String convert (String postfix) {
2.
String operand1, operand2, infix;
3.
Stack<String> s = new AStack<String>;
4.
int i = 0;
5.
while (i < postfix.length) {
char nextc = postfix.charAt (i);
if ((nextc
6.
7.
'+')|| (nextc == '-') {
==
operand2 = s.pop (); operandl = s.pop () ;
infix = '(' + operandl + nextc + operand2 + ')';
s.push (infix); i++;
8.
9.
10.
11.
}
12.
else if (Character.isDigit (nextc)){
int start = i;
while (Character.isDigit (postfix.charAt (i)) i++;
infix = postfix.substring (start, i);
s.push (infix);
13.
14.
15.
16.
17.
}
else i++;
18.
19.
}
20
return s.pop () ;
21. }
(a) Rewrite only the lines of code that need to be changed so that the above function converts a
postfix expression to a prefix expression.
(b) Describe in words what changes are needed on the above given convert () function so that it
also finds the value of the converted postfix expression.
Transcribed Image Text:7. The following function converts a postfix expression to an infix expression assuming the expression can only contain unsigned integer numbers and +' and -' operators. 1. public static String convert (String postfix) { 2. String operand1, operand2, infix; 3. Stack<String> s = new AStack<String>; 4. int i = 0; 5. while (i < postfix.length) { char nextc = postfix.charAt (i); if ((nextc 6. 7. '+')|| (nextc == '-') { == operand2 = s.pop (); operandl = s.pop () ; infix = '(' + operandl + nextc + operand2 + ')'; s.push (infix); i++; 8. 9. 10. 11. } 12. else if (Character.isDigit (nextc)){ int start = i; while (Character.isDigit (postfix.charAt (i)) i++; infix = postfix.substring (start, i); s.push (infix); 13. 14. 15. 16. 17. } else i++; 18. 19. } 20 return s.pop () ; 21. } (a) Rewrite only the lines of code that need to be changed so that the above function converts a postfix expression to a prefix expression. (b) Describe in words what changes are needed on the above given convert () function so that it also finds the value of the converted postfix expression.
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