Required: Adequacy of the SRCB against flexure @ midspan & support based on USD -NSCP 2010. Draw V & M diagram. Use: fy= 41A MPa; fc'=3C MPa; sc=70 mm. A=3mm, B=7mm, C=8mm, D=7mm. DL = 2A KN/m & LL=3B KN/m A=3 B=7 2m 6.D m C=8 D=7 1m 4-2Amm 3C0 6B0 4-2Ammø REBARS SECTION OF SRCB (Units in mm)
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- Question Eight tensile bars with a diameter of 16mm, equally divided into Fwo layers, are developed, C=50mm Spacing between Stirrups = 150 mm center to Center and spacing be tween longitudinal bars is 80 mm if Atr=230 mm? [leastof Cs& cb], Fy = Fyt = 350 M Pa. use Fé = 25,35 and 45 MPa and assume Atr is Satis fied with ACI & BS, Find length of development vequired. > Subject: Advanced Concvete Design, %3DDetermine the capacity of the details shown below. A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi g) what is the flexural/local buckling capacity of the shear plate of the shear connection in kips? (2 decimal places)Problem 01 Using ASD, check the adequacy of the base plate (PL400X350×19 mm) centered on a W12X152 column as shown. It is resting on a concrete pedestal that is 450 mm x 400 mm. The loads are PDL = 600KN and PLL = 320 kN. Use A-36 steel and concrete fc'=20 MPa. TH
- 1. A steel column 10 m long is fabricated from a cover plate and C section arranged as shown. Determine the safe compressive load. Fy = 248 MPa, E= 200 GPa. Use AISC/NSCP Specs. 450 mm -cover plate 'I 12 mm y2 IP d2 10 m C 310 x 37 A = 4720 mm? d = 305 mm bf = 77 mm tf = 12.7 mm tw = 9.8 mm C 310 X 37 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. tw d=305- Ix = 59.9x10° mm ly = 1.85x10° mm x = 17.1 mm x=17.1Determine whether the D = 560 kips L = 68 kips compression member shown is adequate to support the given service loads. Take note Pu = 1.4D. 20' W12 × 79 K = 0.80, r = 3.05 in E = 29000 ksi, Fy = 50 ksi %3D A992 steel Input Yes or No for your final answer. Blank 1 Blank 1 Add your answersted ingid 250MM B k steel bar bolt AUR rigid bar 12 mm thick 8 mm Brass 350mm Jointd 16 mene thick 350mm JointB 250 mm Xg = 20x10% Eg = 90 G Pa -6 A, = 12x10/0 Es = 200 G Pa thickness> 16 mm 8 mm bolt %3D 12 mmi thick shear strength f bolf bearing streng th of holt= 100 la 50 MPa %3D Assume no failure will take place in steel or brass. Temperature chauge brass steel on Temperature change on Determine thai can be applied to system - the max
- Determine the safe load of the column section shown, if it has a yield strength of 25 MPa. E = 200000 MPa. Use NSCP Specifications. Fyz248 mpa Properties of Channel Section d = 305 mm t₂ = 7.2 mm A = 3929 mm² t₁ = 12.7 mm Ix=53.7 x 10mm¹ x = 117 mm Properties of W 460 x 74 A = 9450 mm² b = 190 mm ly= 1.61 x 10 mm x = 17.7 mm tw = 9.0 mm rx = 188 mm ry = 41.9 mm d = 457 mm tr = 14.5 mm Ix = 333 x 10 mm Iy = 16.6 x 10mm* 7.21 When the height of column is 6 m. When the height of column is 10 m. Assume K= 1.0 457 CIVIL ENGINEERING- STEEL DESIGNA 1.5" x1.5" solid steel bar is made of a steel having an Fy = 50 ksi and an Fu = 65 ksi. It is loaded in tension by the following unfactored forces: • DL = 30 kips ● LL = 50 kips • SL 10 kips = Determine if the bar yields in tension. Assume LRFD. Use the ASCE 7-22 Load Combos and Factors.Need complete and elaborate solution A.Using ASD, check the adequacy of the base plate (PL400x350x19 mm) centered on a W12X152 column as shown. It is resting on a concrete pedestal that is 450 mm x 400 mm. The loads are PDL = 600kN and PLL = 320 kN. Use A-36 steel and concrete fc’=20 MPa. B. Using LRFD, PL400x350 mm base plate, W12x120 column, 500x500 mm pedestal, PDL = 1200 kN and PLL = 800 kN. Use A-50 steel and concrete fc’ = 30 MPa. Determine the required base plate thickness.
- Determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksip) what is the tensile yielding capacity of flange plate of the flange connection in kips? (2 decimal places)Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 inThe rigid plate ABC shown in figure 2, was positioned on top of two identical steel posts, and the aluminum post was 0.1mm shorter than the steel posts at temperature of 50°C, if the allowable compressive stress in steel is limited to 120 MPa and in aluminum to 150 MPa, what is the maximum possible load P that can be supported on the rigid plate at temperature of 10°C ?