Remember, even if you enter an answer rounded to a set number of decimal places, if you use that number in a future calculation, you should use all of the decimal places reported on your calculator! Solve triangle ABC if ZA = 41.9°, a = 187.9, and b = 248.6. sin B = (round answer to 5 decimal places) There are two possible angles B between 0° and 180° with this value for sine. Find the two angles, and report them so that B₁ is the acute angle. ZB1 = and ZB2 = (round these and all remaining answers to 1 decimal place) Thus, two triangles satisfy the given conditions: triangle A1B1C1 and triangle A2B2C2. Solve the first triangle: A₁B₁C₁ ZC₁ = and C1 = Solve the second triangle: A2B2C2 LC₂ = and c₂ =

Trigonometry (MindTap Course List)
8th Edition
ISBN:9781305652224
Author:Charles P. McKeague, Mark D. Turner
Publisher:Charles P. McKeague, Mark D. Turner
Chapter2: Right Triangle Trigonometry
Section: Chapter Questions
Problem 6GP
Question
Remember, even if you enter an answer
rounded to a set number of decimal places, if
you use that number in a future calculation,
you should use all of the decimal places
reported on your calculator!
Solve triangle ABC if ZA = 41.9°, a = 187.9, and
b = 248.6.
sin B =
(round answer to 5 decimal places)
There are two possible angles B between 0° and 180°
with this value for sine. Find the two angles, and report
them so that B₁ is the acute angle.
ZB1
=
and
ZB2 =
(round these and all remaining answers to 1 decimal
place)
Thus, two triangles satisfy the given conditions: triangle
A1B1C1 and triangle A2B2C2.
Solve the first triangle: A₁B₁C₁
ZC₁ =
and C1
=
Solve the second triangle: A2B2C2
LC₂ =
and c₂ =
Transcribed Image Text:Remember, even if you enter an answer rounded to a set number of decimal places, if you use that number in a future calculation, you should use all of the decimal places reported on your calculator! Solve triangle ABC if ZA = 41.9°, a = 187.9, and b = 248.6. sin B = (round answer to 5 decimal places) There are two possible angles B between 0° and 180° with this value for sine. Find the two angles, and report them so that B₁ is the acute angle. ZB1 = and ZB2 = (round these and all remaining answers to 1 decimal place) Thus, two triangles satisfy the given conditions: triangle A1B1C1 and triangle A2B2C2. Solve the first triangle: A₁B₁C₁ ZC₁ = and C1 = Solve the second triangle: A2B2C2 LC₂ = and c₂ =
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