Relative precision of traverse is A absolute value of the difference between total distance and adjusted total distance B rise over run c) ratio of linear error of closure to the area of the closed traverse D ratio of linear error of closure to the perimeter of the supposedly close traverse Question 5 Reason to believe that the traverse is not closed. A CL not equal to zero B There are 2 readings made for each traverse line North latitudes not equal to zero East departures not equal to zero E All of the above

Relative precision of traverse is A absolute value of the difference between total distance and adjusted total distance B rise over run c) ratio of linear error of closure to the area of the closed traverse D ratio of linear error of closure to the perimeter of the supposedly close traverse Question 5 Reason to believe that the traverse is not closed. A CL not equal to zero B There are 2 readings made for each traverse line North latitudes not equal to zero East departures not equal to zero E All of the above

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A traverse has the following data: Upload LINE Choose a File AB BC CD DE EA LENGTH 33.48 Use compass rule in adjusting the closed traverse and compute for the Linear Error of Closure and Relative Error of Closure. 8.11 39.42 7.08 22.02 BEARING N 73°23' E $ 39°30' E S43°40' W N 39°50' W N 17°33' W
Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. COMPUTED ADJUSTED DEPARTURE LIN ADJUST ADJUST DISTAN СЕ (M) AZIMUT COMPUTED ADJUSTED LATITUDE ADJUST ED AZIMUT BEARIN DPD DOUBLE E G LATITUDE DEPARTURE ED DISTAN СЕ ED AREA (from S) BEARIN H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ E S 70-29 N 10-00 650.00 ВС 895.00 CD S 26-28 315.00 DE S 65-33 W EA 875.00 410.00 N 45-31 W ТОTAL LEC : RP (nearest hundred) AREA ..
Using the data below, compute for the Linear Error of Closure Also, Determine the adjusted latitude and departure using compass rule: Line Distance Latitude Departure Adjustment (Lat) Adjustment (Dep) Adjusted Lat Adjusted Dep 1-2 388.08 -234.363 -309.322 2-3 732.72 732.665 8.952 3-4 324.78 -22.938 323.969 4-1 477.24 -476.557 -25.531 Express all answer unitless and with 3 decimals for A to J Next
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: Line AB BC CD DA 2- Linear misclosure 3- Traverse precision Length(m) 330 866.8846 411.0045 827 Sum=2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C 1358.7 D 1323.167 A (calculated) 500 Easting 500 491.84 = = Northing 500 170.1 172.62 582.059 500
Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. LIN BEARIN E DISTAN AZIMUT COMPUTED COMPUTED ADJUSTED LATITUDE ADJUSTED DEPARTURE ADJUST ADJUST ED DOUBLE ADJUST ED DPD G СЕ H LATITUDE DEPARTURE ED AREA (M) (from DISTAN BEARIN AZIMUT S) СЕ H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ N 10-00 650.00 BC S 70-29 895.00 1/2 CD S 26-28 315.00 E DE S 65-33 875.00 EA N 45-31 410.00 ТОTAL LEC : RP (nearest hundred) AREA ...
Q1. Calculate departures and latitudes of the following ABCDE traverse. 3 N A 285.40' •N26°10'E E 5 75 25 E 640.45' 647.02' 5306 W N 0°42' W 720.8 203.00 5 15 30¹ W
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the Area of the Traverse. Line Length Bearing AB 589.060 m N 87°30’ E BC 391.730 m N 07°02’ E CD 291.860 m N 30°30’ E DE 656.980 m S 42°45’ E EF 654.060 m Unknown FA 686.660 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
SITUATION A closed traverse has the following data: LINE DISTANCE BEARING N 47° E S 69° E S 39° W S 87° W N 25° W АВ 179.00 258.20 BC CD DE EA ? 145.41 2 What is the length of line CD? 3 What is the length of line DE?
Using the previous exomple, bolance the departures and latitudes using the transit rule. Correer DEP (DEP of course) Corrur"ELAT (LAT of course) OEVALUATE Compute the area of the given traverse using DPD and DMD method. COURSE LENGTH (m) BEARING AB 495.85 NOS" 30' E BC 850.62 N 46° 02' E CD 855.45 S 67* 38 E DE 1020.87 S 12* 25 E EF 1117.26 S 83* 44' W FA 660.08 N 55" 09' W ERSITY
SITUATION 5 A closed traverse has the following data. Line A-B B-C C-A Bearing N 45°00'00" E S 12°00'00" E Distance (m) 1400.00 1800.00
AREA MEASUREMENTS W- E U AREA BY DOUBLE MERIDIAN DISTANCE (DMD) Problem 1: In the tabulation are given the adjusted latitudes and adjusted departures of a closed traverse. V Determine the area using DMD method. LINE ADJUSTED LATITUDE ADJUSTED DEPARTURE (+)N (-)S (+)E (-)W Y AB 113.92 388.84 ВС 178.86 285.13 CD 295.88 134.96 DE 164.35 135.39 EF 13.53 251.86 FA 182.95 151.76 SUM +474.74 -474.74 +673.97 -673.97
Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70