QUESTIONS and PROBLEMS 1. Write the equilibrium constant expression for ... Fe(H₂0)+(aq) + SCN (aq) = K₁ = [Fe NCS2+] [Fe³+] [SCN-1 Fe(H₂0) NCS²+ (aq) + H₂0(1) ૧૪૬૦ 19 2. Calculate an average value of the equilibrium constant from your experimental data. List the values of K, that you averaged; and include an error range with your value of K. (1.1 X102)-(9.3x10') -=935 = 3.5 x 10-3 3. In the equilibrium shown in Question 1, one bond is broken and another bond is formed. a) Consider the strength of the bond broken and the strength of the bond formed. What would the relative strengths of these bonds have to be for this particu- lar reaction to be exothermic? ... endothermic? b) Consider the relative numbers of Fe³+ ions, SCN ions and water molecules in any of your solutions. When Fe(H₂O), NCS²+ forms from the tons, this results (decrease/increase) in entropy. in a(n) c) Considering the entropy change of the forward direction (part b), is the for- ward reaction endothermic or exothermic? Justify. d) Therefore, which bond actually is stronger, the bond that is being made or the bond that is being broken? Justify.
QUESTIONS and PROBLEMS 1. Write the equilibrium constant expression for ... Fe(H₂0)+(aq) + SCN (aq) = K₁ = [Fe NCS2+] [Fe³+] [SCN-1 Fe(H₂0) NCS²+ (aq) + H₂0(1) ૧૪૬૦ 19 2. Calculate an average value of the equilibrium constant from your experimental data. List the values of K, that you averaged; and include an error range with your value of K. (1.1 X102)-(9.3x10') -=935 = 3.5 x 10-3 3. In the equilibrium shown in Question 1, one bond is broken and another bond is formed. a) Consider the strength of the bond broken and the strength of the bond formed. What would the relative strengths of these bonds have to be for this particu- lar reaction to be exothermic? ... endothermic? b) Consider the relative numbers of Fe³+ ions, SCN ions and water molecules in any of your solutions. When Fe(H₂O), NCS²+ forms from the tons, this results (decrease/increase) in entropy. in a(n) c) Considering the entropy change of the forward direction (part b), is the for- ward reaction endothermic or exothermic? Justify. d) Therefore, which bond actually is stronger, the bond that is being made or the bond that is being broken? Justify.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter16: Solubility And Complex Ion Equilibria
Section: Chapter Questions
Problem 8RQ: What is a complex ion? The stepwise formation constants for the complex ion Cu(NH3)42+ are K1 1 ...
Related questions
Question
For 3a, how do I know which bond is stronger (broken or formed) and explain exactly how to use the electrospectral chemical series for this probkem. How do I know if its exothermic or endothermic?
![QUESTIONS and PROBLEMS
1. Write the equilibrium constant expression for ...
Fe(H₂0)+(aq) + SCN (aq) =
K₁ =
[Fe NCS2+]
[Fe³+] [SCN-1
Fe(H₂0) NCS²+ (aq) + H₂0(1)
૧૪૬૦
19
2. Calculate an average value of the equilibrium constant from your experimental
data. List the values of K, that you averaged; and include an error range with
your value of K.
(1.1 X102)-(9.3x10')
-=935 = 3.5 x 10-3
3. In the equilibrium shown in Question 1, one bond is broken and another bond is
formed.
a) Consider the strength of the bond broken and the strength of the bond formed.
What would the relative strengths of these bonds have to be for this particu-
lar reaction to be exothermic? ... endothermic?
b) Consider the relative numbers of Fe³+ ions, SCN ions and water molecules in
any of your solutions. When Fe(H₂O), NCS²+ forms from the tons, this results
(decrease/increase) in entropy.
in a(n)
c) Considering the entropy change of the forward direction (part b), is the for-
ward reaction endothermic or exothermic? Justify.
d) Therefore, which bond actually is stronger, the bond that is being made or the
bond that is being broken? Justify.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F076cf337-ca04-4cd7-8e92-fdbadf0d0ca6%2F1fbb90a0-d3e3-4b66-9d55-f3217b58a369%2Fcddvfdm_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTIONS and PROBLEMS
1. Write the equilibrium constant expression for ...
Fe(H₂0)+(aq) + SCN (aq) =
K₁ =
[Fe NCS2+]
[Fe³+] [SCN-1
Fe(H₂0) NCS²+ (aq) + H₂0(1)
૧૪૬૦
19
2. Calculate an average value of the equilibrium constant from your experimental
data. List the values of K, that you averaged; and include an error range with
your value of K.
(1.1 X102)-(9.3x10')
-=935 = 3.5 x 10-3
3. In the equilibrium shown in Question 1, one bond is broken and another bond is
formed.
a) Consider the strength of the bond broken and the strength of the bond formed.
What would the relative strengths of these bonds have to be for this particu-
lar reaction to be exothermic? ... endothermic?
b) Consider the relative numbers of Fe³+ ions, SCN ions and water molecules in
any of your solutions. When Fe(H₂O), NCS²+ forms from the tons, this results
(decrease/increase) in entropy.
in a(n)
c) Considering the entropy change of the forward direction (part b), is the for-
ward reaction endothermic or exothermic? Justify.
d) Therefore, which bond actually is stronger, the bond that is being made or the
bond that is being broken? Justify.
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