The reaction is measured at three temperatures and the following rate constants have been determined: Rate Constant k Temperature (K) |(M-1.s-1) 277 5.43 x 10-4 300 4.00 x 10-3 319 |2.00 х 10°2 What would you graph if you needed to extract the activation energy from the slope of the graph? (x-axis vs. y-axis) Tvs. k 1/T vs 1/k T vs log(k) OT vs In(k) 1/T vs. In(k) Question In the correct plot from the question above, the slope of the curve is determined to be -7540 K. Note that natural logarithms were used when required. What is the activation energy for this reaction? 907 J-mol 1 -907 J-mol-1 62.7 kJ-mol-1 -62.7 kJ-mol-1 O 144 kJ mol-1 -144 kJ mol-1

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 11.ACP: (Section 11-5) A rule of thumb is that for a typical reaction, if concentrations are unchanged, a...
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please. helpp. this unit is about chemical kinetics. PLEASEE ANSWER BOTH AS THEY ARE PART OF 1 QUESTION ONLY. I REALLY NEED HELP

Question 9
The reaction is measured at three temperatures and the following rate constants
have been determined:
Rate Constant
Temperature
(K)
(M-1.s-1)
277
5.43 x 10-4
300
4.00 x 10-3
319
|2.00 х 10°2
What would you graph if you needed to extract the activation energy from the slope
of the graph?
(x-axis vs. y-axis)
T vs. k
1/T vs 1/k
T vs log(k)
T vs In(k)
O 1/T vs. In(k)
Question
In the correct plot from the question above, the slope of the curve is determined to
be -7540 K. Note that natural logarithms were used when required. What is the
activation energy for this reaction?
907 J-mol1
-907 J-mol-1
62.7 kJ-mol-1
-62.7 kJ-mol-1
144 kJ mol-1
-144 kJ mol-1
Transcribed Image Text:Question 9 The reaction is measured at three temperatures and the following rate constants have been determined: Rate Constant Temperature (K) (M-1.s-1) 277 5.43 x 10-4 300 4.00 x 10-3 319 |2.00 х 10°2 What would you graph if you needed to extract the activation energy from the slope of the graph? (x-axis vs. y-axis) T vs. k 1/T vs 1/k T vs log(k) T vs In(k) O 1/T vs. In(k) Question In the correct plot from the question above, the slope of the curve is determined to be -7540 K. Note that natural logarithms were used when required. What is the activation energy for this reaction? 907 J-mol1 -907 J-mol-1 62.7 kJ-mol-1 -62.7 kJ-mol-1 144 kJ mol-1 -144 kJ mol-1
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