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- Two concentric springs of equal lengths are placed in an assembly shown below. A force P is applied against the plate above. Select all equations among the choices that hold true. No partial points. Note: P is force, ō is change in length. Pouter + Pinner = P Pouter = Pinner = P Souter = dinner douter #dinner P -WwwandMember AB (helical spring) and Member AC (axial rod) are carrying a weight at point A. Member AB has the following properties: R = 90 mm, n -4 turns, G- 70 GPa, d- 30 mm, and Talow = 105 MPa while Member AC has the following properties: L= 2.A- 500 mm?, E = 200 GPa, and a low- 30 MPa. Determine the maximum safe %3D value of W (in N). Use simplified formula for the helical spring. A 60°Topics Discussed: Static of Rigid Bodies, Equilibrium of a Particle, Position Vector, Force Vector Direction, etc. Reminder: Kindly show the complete step-by-step solution. Please make sure that your handwriting is understandable and the picture of the solution is clear. I will rate you with “like/upvote” after. I need the answer right away, thank you. Problem #1: A vertical force P = 20 lb is applied to the ends of the 2-ft cord AB and spring AC. If the spring has an unstretched length of 2 ft, determine the forces, and angle theta for equilibrium. Take k = 25 lb/ft.
- Figure 2 shows an assembly made of a steel tube of internal and external diameter of 20 mm and 30 mm respectively, brass and copper bars, each having 25 mm of diameter. The three materials have equal length of 500 mm and are symmetrically rigidly fixed at the upper end while being joined by a horizontal collar (with negligible mass) at their bottom end. An application of a vertical downward load P on the assembly, results in storing a total of 20 J of energy. Brass Copper Steel Collar Figure 2: A system of steel tube, brass and copper bars The moduli of elasticity for steel, brass and copper materials are Esi=200 GPa, EBr=100 GPa and Ecu=80 GPa, respectively. Calculate: 2.1. The load P if it is applied gradually 2.2. The load P if it is applied suddenly 2.3. The impact load P that falls from a height of 200 mm above the collar.Hi, I have been given this pin-jointed frame analysis to solve (see pictures of the structure attached). Can you help me? The Figure 2 attached is a simplified structure to undertake a structural analysis on a concept design for a low cost stroller/buggy for children. The buggy consists of a number of metal sections that are pin-jointed together. The buggy is designed to accommodate a child of mass no more than 20 kg, sat on the seat which is supported at four points (Fc) on the frame of the buggy. Assume that the weight of the child is equally distributed across all of the points indicated on Figure 2 as Fc. Assume that there are no additional forces applied to the handle of the buggy, that the buggy is static (stationary) and that the buggy, and the elements of the frame have no mass. At points A and G, there are roll supports. At Points B, F and D there are the pin supports. I am required to determine the following: 1) Draw a free-body diagram of the structure 2) Simplify the Free…140 lb 12 lb/in. 8 in. Problem 5-54 what are the values of the reaction forces O r1=150KNM r2=177KN O r1=177KN, r2=150KN O r1=177.9167N, r2=157.0833KN O r1=171.9KN, r2=150KN
- Two concentric springs are constructed with squared and ground ends from oil-hardened steel. The ultimate strength for the steel is 204,000 lbf/in2 . The steel's yield strength is to be estimated as 75% of the ultimate strength. The shear modulus for the steel is 11.5 x 106 bf/in . The springs support a static force of 150 Ibf. The spring dimensions and properties are as follows: Inner spring Mean coil diameter: 1.5 in Wire diameter: 0.177 in Total number of coils: 12.75 Wire diameter: 0.2253 in Free length: 4.5 in Outer spring Mean coil diameter: 2.0 in Free length: 3.75 in Total number of coils: 10.25 A,The deflection of the inner spring is most nearly В. 2.4 in C. 2.9 in B. The maximum shear stress in the inner spring is most nearly B. 52 kips/in2 A. 2.0 in D. 3.1 in A. 47 kips/in2 C.57 kips/in2 D.64 kips/in2 C.The factor of safety in shear for the inner spring is most nearly А. 1.2 D. Specify the winding helix direction for each spring. A. parallel B. right hand B. C. clockwise В.…Two concentric springs are constructed with squared and ground ends from oil-hardened steel. The ultimate strength for the steel is 204,000 lbf/in². The steel's yield strength is to be estimated as 75% of the ultimate strength. The shear modulus for the steel is 11.5 x 106 lbf/in². The springs support a static force of 150 lbf. The spring dimensions and properties are as follows: Inner spring Wire diameter: 0.177 in Mean coil diameter: 1.5 in Total number of coils: 12.75 Free length: 4.5 in Outer spring Mean coil diameter: 2.0 in Wire diameter: 0.2253 in Free length: 3.75 in Total number of coils: 10.25 1. The deflection of the inner spring is most nearly A. 2.0 in B. 2.4 in C. 2.9 in D. 3.1 in 2.The maximum force exerted by the inner spring is most nearly A. 57 lbf B. 67 lbf C. 79 lbf D. 86 lbf 3. The maximum shear stress in the inner spring is most nearly A. 47 kips/in² B. 52 kips/in² C. 57 kips/in² D. 64 kips/in² 4. The factor of safety in shear for the inner spring is most nearly…A helical spring made of oil hardened and tempered steel compression springs, made of circular wire, is subjected to an axial force, which varies from (2.5 KN) to (3.5 KN). Over this range of force, the deflection of the spring should be approximately (5 mm). The spring index can be taken as (5). The spring has square and ground ends. If ultimate tensile strength of (1050 N/mm2) and modulus of rigidity of (81370 N/mm2). The permissible shear stress for the spring wire should be taken as (50 %) of the ultimate tensile strength.Design the spring and calculate the following: 1. Wire diameter; 2. Mean coil diameter; 3. Number of active coils; 4. Total number of coils; 5. Solid length of the spring; 6. Free length of the spring: 7. pitch of coils (p); 8. Required spring rate; 9. Actual spring rate; and 10. Draw a neat sketch .of the spring showing various dimensions
- Design helical compression spring for a service load ranging from 300 N to 375 N. if the permissible shear stress 500 MPa and maximum deflection of the spring for the load range is 8 mm and modulus of rigidity G-80 KN/mm². Draw a fully dimensioned of the spring.Subject: Statics of Rigid Bodies 4. SHOW THE FBD. SOLVE THE SUPPORT REACTIONS OF THE FOLLOWING STRUCTURE: (BEAMS)For the spring assemblages shown in Figure, determine the nodal displacements, the forces in each element, and the reactions. Use the direct stiffness method for all problems. 500 kN/m 500 kN/m Figure P2-15 3 3 1 kN 1000 kN/m 1 kN w