A solution containing 4.60 x 1023 molecules/m3 of protein in water is pure water by a membrane 4.32 µm thick. The diffusion coefficient o through the membrane is 2.30 x 10-18 m²/s. On average, how many
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Q: https://www.youtube.com/watch?v=GxtmnuVioLc Reflection and thoughts of the video
A: link is not working. please provide some other link.
helpasap, my last chance link: https://drive.google.com/file/d/1d5d-ADVTOLson4JhdZbN1KzJISNKrPQz/view?usp=sharing
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- Aromatic molecules like those in perfume have a diffusion coefficient in air of approximately 2×10–5m2/s. Part A Estimate, to one significant figure, how many hours it takes perfume to diffuse 2.5 m, about 6.5 ft, in still air.The small capillaries in the lungs are in close contact with the alveoli. A red blood cell takes up oxygen during the 0.5 s that it squeezes through a capillary at the surface of an alveolus. What is the diffusion time for oxygen across the 1-μm -thick membrane separating air from blood? Assume that the diffusion coefficient for oxygen in tissue is 2×10^−11 m2/s. Give your answer to 1 significant figure.A solution containing 3.76 x 1023 molecules/m3 of protein in water is separated from pure water by a membrane 3.66 μm thick. Measurements show, on average, that 3.79 x 1011 molecules cross 1.05 m2 of the membrane every second. The diffusion coefficient of the protein can be expressed as "D" x 10-18 m2/s. What is the calculate the value of the number "D". [Answer with 3 sig digits, but do not enter units with your answer]
- Q 2: a- If you had 0.2 kg of helium, how many helium atoms would you have? b- If you had 10 dozen helium atoms, what would be their mass? c- What is the mass of one helium atom? d- What is the mass of 2.0 moles of helium atoms?A water molecule has a diameter of about 0.275 nm. How many hours would it take for a water molecule to diffuse across the surface of a Starbucks Venti sized cup of coffee whose diameter is 3.8 inches? Assume that coffee is liquid H20 for your calculation. The diffusion coefficient of H2O in water is 2.26 X 109 m2sThe basic function of an automobile's carburetor is to atomize the gasoline and mix it with air to promote rapid combustion. Assume that 40 cm? of gasoline is atomized into N spherical droplets. Each droplet has a radius of 2.0 x 10-5 m. Find the total surface area of these N spherical droplets.
- Diffusion WS Name 2. Methylene chloride is a common ingredient of paint removers. Besides being an irritant, it also may be absorbed through skin. When using this paint remover, protective gloves should be worn. If butyl rubber gloves (0.04 cm thick) are used, what is the diffusive flux of methylene chloride through the glove? Diffusion coefficient in butyl rubber D = 110 x 10-8 cm²/s. Concentrations on the outside and inside surfaces of the glove are C₁ = 0.44 g/cm³, C₂ = 0.02 g/cm³. wing ve the 12You can smell perfume very shortly after opening the bottle. To show that it is not reaching your nose by diffusion, calculate the average distance a perfume molecule moves in one second in air, given its diffusion constant D to be 1.00 • 10–6 m2/s.Numeric : A numeric value is expected and not an expression.xrms = __________________________________________A typical sugar cube has an edge length of 1 cm. If you had a cubical box that contained a mole of sugar cubes, what would its edge length be?
- f the density of air is 1.25 × 10-3 g/cc, what is the mass in kilograms of the air in a room that is 5.3 m long, 4.2 m wide, and 2.0 m high?a 25cm diameter cylinder that is 36cm long contains 60g of oxygen gas at 20 degree c what is the number density of the oxygen? (express in molecules per meter cubed) what is the reading of a pressure gauge attached to the tank? (express with appropriate units)Growth rate of bamboo Bamboo belongs to the grass family andis one of the fastest growing plants in the world.a. A bamboo shoot was 500 cm tall at 10:00 A.M. and 515 cm tallat 3:00 P.M. Compute the average growth rate of the bambooshoot in cm/hr over the period of time from 10:00 A.M. to 3:00 P.M.b. Based on the Mean Value Theorem, what can you concludeabout the instantaneous growth rate of bamboo measured inmillimeters per second between 10:00 A.M. and 3:00 P.M.?