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- a = 1.2 m b = 1.8 m c = 4 m Force AB - 500 Newtons FAB Find the y-component of unit vector AC. (Hint: the value should be less than 1). If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign. Find the z-component of unit vector AC. (Hint: the value should be less than 1). Find the x-component of Force AB in N.10 İnch, 300 B Inch 20 5 ft 5inch 100 Ib 16 ft Mass of the AB bar in the I profile form in the system loaded as shown in the figure 100 kg / m; Using magnitudes translated into the SI system of units; Question 4: Find the intensity and direction (0) of the compound force acting on bearing aQuestion #3: In the figure below, a 100 N weight flower pot is suspended by three ropes. The tension in rope AB is three times the tension in ropes AC and AD. Find the dimension “d” on the figure which corresponds to the z-coordinate of point B. Also find the tensions in ropes AB, AC, and AD. Please do each step as I am trying to check my answers. I got to the point of setting the ijk components equal to zero. I'm stuck at multiplying the tension in vector AB times 3.
- a = 1.2 m b = 1.8 m C= 4 m Force AB = 500 Newtons FAB A Find the z-component of unit vector AB. (Hint: the value should be less than 1). If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign. Find the Length of AC in m. Find the x-component of unit vector AC. (Hint: the value should be less than 1).The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. d 2 Pl CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m С. 62,5 N*m D. Object 1 doesn't exert a torque.3) A point mass is attached to one end of a beam levered against a spike which acts as the pivot. The point mass weighs 250N and the beam has a uniform mass of 10kg and is 8m long. Parts a and b Part c Fapplied 3 of 6mov 1m 8m Krist 0 = 60° Scale 250 N Scale a. If a scale placed beneath the point mass reads 250N, what is the magnitude and direction for the force at the pivot point? Direction: North, 90° from x-axis Magnitude to k* 250N = 2500 N b. For the same scenario, how far must the pivot point be located relative to the left edge of the beam? (Hint, both the boxes weight and the force from the scale act at the farthest right edge of the beam.) www.acta 0672nos onl c. The pivot is then moved to be 6m from the left edge of the beam which now makes a 60 angle with the floor. How much downward force would be needed at the left-most edge of the beam to reduce the reading on the scale to zero? (Hint: the beam is still in static eq. when the scale reads zero.)
- a = 1 m b = 2 m c = 3 m Force AB = 500 Newtons FAB Find the y-component of unit vector AC. (Hint: the value should be less than 1). Find the z-component of unit vector AC. (Hint: the value should be less than 1). Find the x-component of Force AB in N. If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign.In figure 3, small piston {1} with face cross sectional area of 0.3 m2 received 9 kN force and delivered it to larger piston {2} with face cross sectional area of 0.6 m2, determine the force delivered to large piston {2}. {1} {2}. F42 in 64 [in]- 50 in D 59 in B ی به سوالات فهد اما او شده وام بانک سامانه 63 in -10 in 21 in Given: The plate( The shaded rectangular volume) has weighs 240 lbf. It is. suspended bycable CD, Which D is wall anchor. So, Find the magnitude of force in the cable CD such the system is in static equilibrium??. Show all works.
- Consider the forces acting on the bracket shown in (Figure 1). Figure Submit VG ΑΣΦ 459 (F₁)z. (F1), (F₁) = Determine the coordinate angle y for F2.(Figure 1) Express your answer in degrees to three significant figures. Submit Request Answer (F2), (F2), (F2), = /30 ΑΣΦ | 11 60% F₂ = 600 N Submit Request Answer VAX 1 vec vec X Incorrect; Try Again; 4 attempts remaining F₁ = 450 N Previous Answers Request Answer Express the force F₁ as a Cartesian vector. Enter the components of the force separated by commas. Express your answers in newtons to three significant figures. ——| ΑΣΦ | |t | vec 195| | S 1 of 1 A @ GERIC ? Express the force 12 as a Cartesian vector. Enter the components of the force separated by commas. Express your answers in newtons to three significant figures, N ? ? N/Find the two forces Fbc & Fac as shown :in the figure below Fab=30 N Fbc 50 30 Fac (Fbc=55 N and Fac= 70 N) O (Fbc=40 N and Fac= 50 N) O (Fbc=46 N and Fac= 59 N) Oa = 1.2 m b = 1.8 m c = 4 m Force AB - 500 Newtons B FAB Find the Length of AB in m. If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign. Find the x-component of unit vector AB. (Hint: the value should be less than 1). Find the y-component of unit vector AB. (Hint: the value should be less than 1).