Question 2: Write the MIPS code for the given Hexadecimal Machine Code that starts at memory address 0x 40000. Line1: 0x0080082A Line2: 0x14200002 Line3: 0x2084FFFF Line4: 0x08010005 Line5: 0x20840001 Line 6: 0x1480FFFA Line7: 0x03E00008 Line8: 0x0C010000
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Question 2: Write the MIPS code for the given Hexadecimal Machine Code that starts at memory address 0x
40000. Line1: 0x0080082A Line2: 0x14200002 Line3: 0x2084FFFF Line4: 0x08010005 Line5: 0x20840001 Line
6: 0x1480FFFA Line7: 0x03E00008 Line8: 0x0C010000
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- Most Intel CPUs use the __________, in which each memory address is represented by two integers.Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What is the Value of r0 and r1 after executing LDR r1, [r0, #2] -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]Suppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
- Consider the following hexadecimal readout: 000000 8A00 8E00 CFA1 48BF 7900 3202 9015 AD34 000010 0218 6D30 028D 3402 AD35 0288 3102 8D35 000020 0E30 0290 DAEE 3102 4C00 0200 0040 004B Refer to the first byte of memory shown above, address 000000. Assume that this byte is used to store an 8-bit unsigned integer. What is the decimal value stored in this byte? Group of answer choices 138 -27 22,842 66The 32-bit number 52AB43FC (in hexadecimal) is stored in abyte-addressable memory starting at physical address FE08 (in hex) using Little-Endian notation. The byte(value ni hexadecimal) stored at theaddress FE0B will beQUESTION 9 What is the hexadecimal representation of the memory variable location at address 003FBA03H in the Little Endian format from the 32-bit binary quantity represented by 10100111 110111100101101100001100b? Address in hexadecimal format 003FBA00H 003FBA01H 003FBA02H 003FBA03H 003FBA04H Data in hexadecimal format O a. The hexadecimal representation for the variable located at memory address 003FBA03 is A8. Ob. The hexadecimal representation for the variable located at memory address 003FBA03 is A5. OC. The hexadecimal representation for the variable located at memory address 003FBA03 is A3. Od. The hexadecimal representation for the variable located at memory address 003FBA03 is A7.
- if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical address is O 6243H O 4234H O 6234H O 6324H O 4244HPlease complete the binary encoding for the following BL instruction at address Ox2000 using the given information. Please write the answer in a group of four bits as follows: 0010 0010 0010 1100. Address Instructions 0x2000 bl sub 0x2004 add r3, r2, r1 0x2008 sub r6, r5, r3 sub: stmfd r13!, {r0-r12, 0X200C r14] 0x2010 add r7, r2, r5 Ox2014 mov r3, r2By assuming that X = 3, and 33 is a two digit number, consider memory storage of a 64-bit word stored at memory word 33 in a byte-addressable memory (a) What is the byte address of memory word 33? (b) What are the byte addresses that memory word 33 spans? (c) Draw the number 0xF1234567890ABCDE stored at word 33 in both big endian and little-endian machines. Clearly label the byte address corresponding to each data byte value.
- Q1- Write a program in assembly language for the 8085 microprocessor to receive 10 bytes of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When you receive each byte of the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception (start bits), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit). The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes The solution must be integrated and include the calculation of the baudrate delay time Of+CD!HID+[00 Yes SIDATA Read SID Start Bit? Wait for Half-Bit Time Set up Bit Counter Wait Bit Time Read SID Save Bit Decrement Bit Counter All Bits Received? Add Bit to Previous Bits Go Back to Get Next Bit Return IMUNIQ2- Write a program in assembly language for the 8085 microprocessor to receive one byte of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz . When receive the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception(start bits 1 1 ), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit 0 ). The following flowchart will help you. The solution must be integrated and include the calculation of the baudrate delay timeA CPU that supports little endian format reads two integer (4-byte) values from address 0x1000 and 0x2000. The values read are 55 and 6850 respectively. Please show the memory contents (byte-wise) at address 0x1000 and 0x2000?