QUESTION # 2: The lap joint of a tension member is shown in the figure. The plate is 252 mm wide and 12 mm thick. The A325 bolts are 20 mm in diameter and the holes are 3 mm larger than the bolt diameter. Steel is A36. It is required to determine the ultimate capacity of the joint based on gross area, net area, and block shear. Use LRFD specifications and assume that live load to dead load ratio is equal to 3.0. A325 Bolts Properties: Fnt = 620 MPa Fnv= 469 MPa A36 Properties: Fy = 248 MPa Fu = 400 MPa Figure 2 63 mm 63 mm 38 mm 38 mm - ↑ 63 mm 63 mm 1+ 63 mm 63 mm O O O оо оо OO OO t=12mm 252 mm

QUESTION # 2: The lap joint of a tension member is shown in the figure. The plate is 252 mm wide and 12 mm thick. The A325 bolts are 20 mm in diameter and the holes are 3 mm larger than the bolt diameter. Steel is A36. It is required to determine the ultimate capacity of the joint based on gross area, net area, and block shear. Use LRFD specifications and assume that live load to dead load ratio is equal to 3.0. A325 Bolts Properties: Fnt = 620 MPa Fnv= 469 MPa A36 Properties: Fy = 248 MPa Fu = 400 MPa Figure 2 63 mm 63 mm 38 mm 38 mm - ↑ 63 mm 63 mm 1+ 63 mm 63 mm O O O оо оо OO OO t=12mm 252 mm

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter3: Tension Members

Section: Chapter Questions

Problem 3.3.4P

See similar textbooks

Similar questions

The tension member shown in the figure is a PL1/⁄2”X8” of ASTM A36 steel. The member is connected to a gusset plate with inch diameter bolts. It is subjected to the dead and live loads shown. Does this member have enough strength? Assume that . a) Per LRFD b) Per ASD 00 O D=95k L=9k PL 12 x 8
4. An UPE 300 is to be used as a tension member and it is bolted to a 10mm thick gusset plate with bearing type 8-M20 8.8 bolts as shown in the figure below. a. Check all spacing and edge distance requirements. b. Compute the allowable tensile strength of the channel UPE 300. Don't consider shear strength of the bolts and bearing strength of the bolt holes. [all dimensions are in mm] Material both for gusset plate and UPE 300: S275 F-275N/mm² Fu=430N/mm² UPE 300 Ag = 5660 mm² tw 9.5 mm x = 28.9 mm 70 160 70 + 10mm thick gusset plate +50+ 80 -80-80-50 o +50+80 -80 80-50 UPE 300
STAGGERED CONNECTIONS: A PLATE WITH WIDTH OF 400 mm AND THICKNESS OF 12 mm IS TO BE CONNECTED TO A PLATE OF THE SAME WIDTH AND THICKNESS BY 34 mm DIAMETER BOLTS, AS SHOWN IN THE FIGURE. THE HOLES ARE 2 mm LARGER THAN THE BOLT DIAMETER. THE PLATE IS A36 STEEL WITH YIELD STRENGTH Fy = 248 MPa. ASSUME ALLOWABLE TENSILE STRESS ON NET AREA IS 0.60Fy. IT IS REQUIRED TO DETERMINE THE VALUE OF b SUCH THAT THE NET WIDTH ALONG BOLTS 1-2-3-4 IS EQUAL TO THE NET WIDTH ALONG BOLTS 1-2-4. a. CALCULATE THE VALUE OF b IN MILLIMETERS. b. CALCULATE THE VALUE OF THE NET AREA FOR TENSION IN PLATES IN SQUARE MILLIMETERS. c. CALCULATE THE VALUE OF P SO THAT THE ALLOWABLE TENSILE STRESS ON NET AREA WILL NOT BE EXCEEDED.
2. For the figure shown, calculate the net area of the 10 x 200 mm plate. The plate is connected at its end with two lines of 20 mm bolts. Using LRFD, determine the load P that the plates can carry against tensile yielding in the gross section and the tensile rupture in the net section. Use A-36 steel. PL 5x200mm PL 5x200mm Pu PL 10x200mm Pu
A flanged bolt coupling consists of 6 - 12 mm - diameter bolts on a bolt circle of 320 mm in diameter. Compute the number of additional 10 mm - diameter bolts on a bolt circle 200 mm in diameter to increase the torque capacity to 7.65 kNm. The shearing stress of the bolts should not exceed 60 MPa. Select one: O a. 6 bolts O b. 4 bolts O c. 3 bolts O d. 2 bolts NEXT PAGE
Problem (4): A36 steel is used for the tension member shown in Figure below. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the net area. PL 300mmx17mm 150 75 75 75 75 75 125 ImmmmTmm"" mmn mm mm 50mm 100mm 100mm 50mm 19mm diameter bolts Problem (5): The tension m shown in Figur
Considering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.
4. As shown below, the splicing joint of a beam was made with bearing type high-strength bolts. The loads transferred through the joint is V=3000KN, M=90KN.m. The bolts are of grade 10.9, nominal diameter 22mm, effective area Ae=2.45cm2;f=310N/ mm?; f-500N/mm²; End plates made of Q235B steel, thickness 22mm, fe-470N/mm?. Check the strength of this bolt connection. -24mm 35 130 35 80 V 1 og1 081 1 081
The connection shown is subjected to a tensile force of P = 100 kN. The allowable shear stress for the bolts is 100 MPa. Assume each bolt supports an equal portion of the load. Determine the required diameter of the bolts. a. 20.6 mm b. 25.2 mm c.35.7 mm d.17.8 mm choose letter of correct answer
Topic:Bolted Steel Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A channel shown is attached to a 12 mm gusset plate with 9-22 mm diameter A 325 bolts as shown. Use LRFD. Fnv = 300 MPa Fu = 400 MPa Fy = 248 MPa Ag = 3354 mm2 Question: Determine the capacity of the channel based on the bearing strength of the connection.
As shown in the figure below, a C7 x 12.25 tension member of A572 Gr 50 steel is connected to the gusset plate using 20-mm diameter bolts. Using equation 3.1 to evaluate the value of U, calculate the allowable strength of the member. 38 mm 50 mm 50 mm 75 mm 75 mm ооо 38 mm t = 9.5 mm Pa C7 x 12.25
Use ASD to determine the width of the 5/8 inch thick A36 plate subjected to tension as shown below. The dead load effect is PD=85 kip while the live load effect is PL=80 kip. Two rows of 5/8 inch standard bolts will be used for the connection and the plate width can be manufactured in 1 inch increments. Assume that the larger connected plate does not fail. Consider the limit states of gross tensile yield and tensile rupture. Find the required tension strength, Pa, for the controlling ASD load combination. Determine the width necessary for the plate to resist gross tensile yield. Determine the width necessary for the plate to resist tensile rupture. Report the required plate width.