QUESTION 10 11 A convolutional circuit has three internal registers (s0, s1, and s2), and three outputs (co, c1 and c2), calculated as follows: c0=i+s0; c1=i+s1+s2; c2=s0+s2. We are currently in state 110 and receive input 0. What is the output and next state? O c0=1; c1=1; c2=0; next=011 O c0=1; c1=1; c2=1; next=011 O c0=0; c1=1; c2=0; next=011 O c0=1; c1=0; c2=1; next=011 O c0=0; c1=0; c2=1; next=011 QUESTION 11 13 A convolutional circuit has three internal registers (S0, S1, and s2), and three outputs (c0, c1 and c2), calculated as follows: c0=i+s1; c1=i+s1+s2; c2=s0+s2. We are currently in state 011 and receive input 0. What is the output and next state? O c0=0; c1=1; c2=0; next=001 O c0=1; c1=0; c2=1; next=001 O c0=1; c1=1; c2=0; next=001 O c0=1; c1=1; c2=1; next=001 O c0=0; c1=0; c2=1; next=001 QUESTION 12 20 A convolutional circuit has three internal registers (S0, S1, and s2), and three outputs (co, c1 and c2), calculated as follows: c0=i+s1; c1=i+s0+s2; c2=s0+s1. We are currently in state 011 and receive input 1. What is the output and next state? O c0=0; c1=1; c2=0; next=101 O c0=1; c1=0; c2=1; next=101 O c0=0; c1=0; c2=1; next=101 O c0=0; c1=0; c2=0; next=101 O c0=1; c1=1; c2=0; next=101

QUESTION 10 11 A convolutional circuit has three internal registers (s0, s1, and s2), and three outputs (co, c1 and c2), calculated as follows: c0=i+s0; c1=i+s1+s2; c2=s0+s2. We are currently in state 110 and receive input 0. What is the output and next state? O c0=1; c1=1; c2=0; next=011 O c0=1; c1=1; c2=1; next=011 O c0=0; c1=1; c2=0; next=011 O c0=1; c1=0; c2=1; next=011 O c0=0; c1=0; c2=1; next=011 QUESTION 11 13 A convolutional circuit has three internal registers (S0, S1, and s2), and three outputs (c0, c1 and c2), calculated as follows: c0=i+s1; c1=i+s1+s2; c2=s0+s2. We are currently in state 011 and receive input 0. What is the output and next state? O c0=0; c1=1; c2=0; next=001 O c0=1; c1=0; c2=1; next=001 O c0=1; c1=1; c2=0; next=001 O c0=1; c1=1; c2=1; next=001 O c0=0; c1=0; c2=1; next=001 QUESTION 12 20 A convolutional circuit has three internal registers (S0, S1, and s2), and three outputs (co, c1 and c2), calculated as follows: c0=i+s1; c1=i+s0+s2; c2=s0+s1. We are currently in state 011 and receive input 1. What is the output and next state? O c0=0; c1=1; c2=0; next=101 O c0=1; c1=0; c2=1; next=101 O c0=0; c1=0; c2=1; next=101 O c0=0; c1=0; c2=0; next=101 O c0=1; c1=1; c2=0; next=101

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 9VE

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9. A multiplexer is a switching circuit that produces as its single output one of a set of inputs based on the value of some additional inputs called the controls. Given that 0, 1, 2, and 3 in two-bit binary are 00, 01, 10, and 11, respectively, draw a 2-bit multiplexer using the three basic logic gates with inputs xo, x1, x2, and x3, and two control inputs co and c1. Setup the circuit so that x; is the single output, where i if the value of the 2-bit integer (cico)2. NOTE: This is not a Boolean product; instead it's the binary representation of an integer where c1 is the most significant bit and co is the least significant bit.
06 A convolutional circuit has three internal registers (S0, S1, and s2), and two outputs (CO and c1), calculated as follows: c0=i+s0; c1=i+50+s1. We are currently in state 110 and receive input 1. What is the output and next state? O c0=0; c1=1; next=111 c0=0; c1=0; next=111 c0=1; c1=0; next=111 c0=1; c1=1; next=111 QUESTION 8 35 A convolutional circuit has three internal registers (S0, S1, and s2), and two outputs (co and c1), calculated as follows: c0=i+s2; c1=i+50+s1. We are currently in state 110 and receive input 0. What is the output and next state? c0=0; c1=0; next=011 c0=1; c1=0; next=011 c0=1; c1=1; next=011 c0=0; c1=1; next=011
QUESTION 5 13 A convolutional circuit has three internal registers (s0, s1, and s2), and two outputs (c0 and c1), calculated as follows: c0=i+s1; c1=i+s1+s2. We are currently in state 011 and receive input 0. What is the output and next state? c0=0; c1=1; next=001 c0=0; c1=0; next=001 c0=1; c1=0; next=001 c0=1; c1=1; next=001
5. Design a logic circuit with 3-bit inputs A, B, C that produces an output W, X, Y, Z that is equal to the input + 6 (110) in binary. For example If the input is equal to 5 decimal then the output should be 5+6=11 decimal, the circuit will take all numbers in binary form and the output will also be in binary (101)B + (110)B=(1011)B
QUESTION 5 35 A convolutional circuit has three internal registers (s0, s1, and s2), and two outputs (c0 and c1), calculated as follows: c0=i+s2; c1=i+s0+s1. We are currently in state 110 and receive input 0. What is the output and next state? O c0=0; c1=0; next=011 O c0=1; c1=0; next=011 O c0=1; c1=1; next=011 O c0=0; c1=1; next=011 QUESTION 6 11 A convolutional circuit has three internal registers (S0, S1, and s2), and two outputs (c0 and c1), calculated as follows: c0=i+s0; c1=i+s1+s2. We are currently in state 110 and receive input 0. What is the output and next state? O c0=1; c1=1; next=011 O c0=0; c1=1; next=011 O c0=0; c1=0; next=011 O c0=1; c1=0; next=011 QUESTION 7 02 A convolutional circuit has three internal registers (s0, s1, and s2), and two outputs (c0 and c1), calculated as follows: c0=i+s0; c1=i+s0+s1. We are currently in state 011 and receive input 1. What is the output and next state? O c0=0; c1=1; next=101 O c0=0; c1=0; next=101 O c0=1; c1=0; next=101 O c0=1; c1=1;…
Task: DL34. In digital electronics, a NAND gate (NOT-AND) is a logic gate which produces an output which is false only if all its inputs are true; thus, its output is complement to that of an AND gate. A LOW (0) output results only if all the inputs to the gate are HIGH (1); if any input is LOw (0), a HIGH (1) output results. A NAND gate is made using transistors and junction diodes. Minimum number of NAND gates required to implement the following binary equation (A'+B') (C+D)?
in The architecture of the following circuit can be expressed as: X1 x3 X2 f <= (x1 AND x3) OR (x2 AND x4); g <= (x1 OR NOT x3) AND (NOT x2 OR x4); Select one: O True ▼ False g
= 1 causes the heater to decrease its Q3: A Moore sequential circuit has three inputs (X2, X1, and Xo) that specify a temperature range in a room. The circuit has two outputs (I and D) that control a heater for the room; I = 1 causes the heater to increase its heat output, and D heat output. If the temperature range is 0, 1, or 2 for three successive clock cycles, the circuit generates I = 1, and conversely if the temperature range is 5, 6, or 7 for three successive clock cycles, the circuit generates D = 1; otherwise, I = 0 and D = 0. 1. Draw a state diagram. 2. Construct a state table. 3. Using D flip-flops, construct a state assigned table. 4. Determine the next-state and output logic expressions. 5. Sketch the corresponding logic circuit.
2. A logic circuit realizes the function F(A,B,C,D) = A' B' + A' C D+ A C' D+ A B' D'. Assuming that A= C never occurs when B = D= 1, find a simplified expression for F.
1a. Draw a circuit diagram using appropriate logic gates to implement a 3-bit comparator. Identifythe gates used in implementation and show its usage to compare two 3-bit words by writing thetruth table. b. Write the Boolean expression for the following 4 input circuit. Include sub-expressions foroutputs of each gate. c. Complete a truth table for the previous logic gate circuit in part b. d. Write the Boolean expression for the new circuit below. Then, simplify the following logic circuitusing the theorems in Boolean algebra. Show the steps clearly and specify the law used in eachstep. Finally draw the simplified circuit diagram.
combinational circuit has 3 inputs A, B, C and output F (A,B,C). F is true when (A is False and B is True), or (A is False and Cis True), or (A and B and C) are False, or (A and B and C are True). The function can be represented as F(A,B) = T M(4, 5, 6) a F(A,B) = E m(0, 1, 2, 3, 6, 7) b O F(A.B) = TT M(0, 1. 2. 3, 7) .c O %3D F(A,B) = E m(0, 1. 2. 6. 7) d O
2. Design a combinational circuit with three inputs, x, y, and z, and three outputs, A, B, and C. When the binary input represents any of the decimal digits 1, 2, 3, or 6, the binary output should represent the decimal digit that is one greater than the input, that is 2, 3, 4 and 7, respectively. Similarly, when the binary input represents any of the digits 4, or 7, the binary output should represent the digit that is two less than the input. The remaining two inputs, that are the binary representations of the decimal digits 0 and 5 never occur. Draw the truth table, and give all the minimal forms for the functions that represent the outputs A, B, and C. U