Question 1. What is the time complexity for the following code/program? 1.1 for (int i = 1; i <= n; i++){ for (int j = 1; j <= n; j++){ 1.2 int a = 0; for (int k = n; k >= 1; k--){ sum = i + j+k; cout << sum << endl;}}} for (i = 0; i < N; i++) { for (j=N; j>i; j--) { a = a +i+j;}} 1.3 for (int i = 1; i <= n; i++){ for (int j = 1; j <= 100; j++){ sum = i + j + k;}}

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Question 1. What is the time complexity for the following code/program?
1.1
for (int i = 1; i <= n; i++){
for (int j = 1; j <= n; j++){
1.2
int a = 0;
for (int k = n; k >= 1; k--){
sum = i + j + k;
cout << sum << endl;}}}
for (i = 0; i < N; i++) {
for (j=N; j>i; j--) {
a = a +i+j;}}
1.3
for (int i = 1; i <= n; i++){
for (int j = 1; j <= 100; j++){
sum = i + j + k;}}
1.4
for (int i = 0; i<n; i++){
for (int j = i; j> 0; j = 2){
cout <<j << endl; } }
1.5 A binary search works like this: in a sorted array, the search algorithm compares the target value to
the middle element of the array. If they are not equal, the half in which the target cannot lie is eliminated
and the search continues on the remaining half, again taking the middle element to compare to the target
value and repeating this until the target value is found. If the search ends with the remaining half being
empty, the target is not in the array. What is the complexity of binary search? Why?
Transcribed Image Text:Question 1. What is the time complexity for the following code/program? 1.1 for (int i = 1; i <= n; i++){ for (int j = 1; j <= n; j++){ 1.2 int a = 0; for (int k = n; k >= 1; k--){ sum = i + j + k; cout << sum << endl;}}} for (i = 0; i < N; i++) { for (j=N; j>i; j--) { a = a +i+j;}} 1.3 for (int i = 1; i <= n; i++){ for (int j = 1; j <= 100; j++){ sum = i + j + k;}} 1.4 for (int i = 0; i<n; i++){ for (int j = i; j> 0; j = 2){ cout <<j << endl; } } 1.5 A binary search works like this: in a sorted array, the search algorithm compares the target value to the middle element of the array. If they are not equal, the half in which the target cannot lie is eliminated and the search continues on the remaining half, again taking the middle element to compare to the target value and repeating this until the target value is found. If the search ends with the remaining half being empty, the target is not in the array. What is the complexity of binary search? Why?
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