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Genetics Q1
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- Question 5 Review DNA sequencing and cloning tools. Which of these is not used to make a recombinant DNA? O restriction enzymes to create sticky ends of a plasmid O fragment from a different DNA cut by the same restriction enzyme O DNA ligase seals the recombinant DNA O denaturationQUESTION 5 Match the vocabulary word with the proper definition: enzyme that joins two pieces of DNA ✓ first human protein to be produced by genetic engineering 00000 ✓ process that makes many copies of a gene or other DNA segment the process of isolating and making copies of a gene ✓ the process of placing recombinant DNA into a living cell circular DNA that is not part of a chromosome V genetically modified plants changing an organism by transforming with recombinant DNA DNA ligase II. recombinant DNA III. transgenic crop IV. polymerase chain reaction V. gene cloning VI. genetic engineering VII. transformation VIII. plasmid IX. biotechnology X. insulin the use of technology to change the genetic makeup of living things for human purposes made by joining DNA from two differentQuestion 7 Review DNA sequencing and cloning tools. The direct manipulation of genes is called genetic engineering DNA sequencing nucleic acid hybridization gene cloning O recombination DNA
- QUESTION 7 Primers are needed to start a PCR reaction True O False QUESTION 8 Restriction enzymes specifically recognize and cut short sequences of DNA called introns. O exons. O sticky ends. restriction sites. QUESTION 9 The DNA profiles used as evidence in a murder trial look something like supermarket bar codes. The pattern of bars in a DNA profile shows O the order of genes along particular chromosomes O the order of bases in a particular gene O the presence of differently-sized fragments of DNA O the presence of dominant or recessive alleles for particular traits O the number of chromosomes and whether any are damagedQuestion 1. Restriction endonucleases can be isolated from a number of bacteria. In bacteria restriction endonucleases. a-restrict chromosomal DNA that is heavily mutated b-restrict chromosomal DNA with significant regions that have been Deleted. c-restrict the DNA of invading bacteriophages. d- all of the above Question 2. In a PCR reaction the step in which DNA polymerase replicates the DNA is referred to as a- denaturation b- annealing C- extension d- initiationQuestion 16 Why can't SNPS be detected by PCR and Gel Electrophoresis? O Because Gel Electrophoresis detects size differences in DNA and SNPS do not change the size of the DNA strand. O Because SNPS cause deletions so large that they are beyond the limits of this technique to detect. O Because SNPS affect proteins and PCR only works on DNA. O Because SNPS are too complicated to detect with this technology.
- Question 32 Enzyme that combines the 2 DNA fragments from different organisms Recombinant DNA Technology Restriction enzymes O Ligase O Palindromic sequencesQuestion 8. You isolate the DNA from the bacterial cells and apply the Sanger dideoxy sequencing method. You then separate the products of the reactions by gel electrophoresis and obtain the following pattern. What is the sequence of the template and the DNA on the gel? ddATP ddTTP ddCTP ddGTP Template V [ Choose 3'-CTAGTCAAGG-5' 5'-CTAGTCAAGG-3' Sequence 3'-GATCAGTTCC-5' 5'-GATCAGTTCC-3' 5'-GGAACTGATC-3'Instructure.com/courses/47420/quizzes/225324/take missour Question 2. It is your first week working in the lab but unfortunately you program the PCR machine incorrectly and some of your PCR experiments do not work as expected. For each of the following scenarios, state at which step the PCR went wrong, what was wrong and what would have happened. Cycles Which step is incorrect? Is the temp too high or too low? Experiment of What happened? PCR Step 1 94 °C Step 94°C V [ Select ] [ Select ] [ Select ] a step 2 Step 3 72 °C step 3 step 1 Step 1 30 °C Step 2 60 °C [ Select ) [ Select ] [ Select ] Step 3 72 °C Step 1 94 °C [ Select] Step 2 22°C [ Select ] [ Select ] Step 3 72 °C 8 A átv
- QUESTION 1 You want to perform PCR on the CDNA of the spike gene from a SARS CoV-2 sample so that you can sequence it. Based on the sequence below, which of the following primer pairs would probably work for PCR of this gene? Spike gene Sequence: 5' ATGTTTATTTTCTTATTATTTTTTACTCTCACTAGTGGTAGTGACCTTGACCGGTGCACCACTTTTGATG ATGTTCAAGCTCCTAATTACACTCAACATACTTCATCTATGAGGGGGGTT TACTATCCTGATGAAATTTT. .. (it's really long so didn't post the whole thing.).TCTTGCTTTGTTGCATGACTAGTTGTTGCAGTTGCCTCAAGGGTGCATGCTCTTGTGGTTCTTGCTGCAA GTTTG ATGAGGATGACTCTGAGCCAGTTCTCAAGGGTGTCAAATTACATTACACATAA 3' Forward primer: 5' - CTC TCA CTA GTG GTA GTG ACC - 3' (Tm = 60.5 °C in a standard qPCR mix) Reverse Primer: 5' GGG TGT CAA ATT ACA TTA CAC ATA - 3' (Tm= 59.6 °C in a standard QPCR mix) Forward Primer: 5'- ATG TTT ATT TTC TTA TTA TT -3' (Tm=D 47.2 °C in a standard qPCR mix) Reverse Primer: 5'- GCA AGA ACC ACA AGA GCA TGC ACC -3' (Tm= 68 °C in a standard qPCR mix) Forward primer: 5' - CTC TCA CTA GTG GTA GTG ACC -3'…Joe is heterozygous for a dominant genetic disease. His wife, Jenny does not have the disease. They have 5 children of which 2 (Jim and Jan) have the disease and 3 (Jose, Jerry and Julie) do not. DNA from each individual is isolated and analyzed by PCR an gel electrophoresis. 3 variable markers are studied. The results for each marker are shown here. The numbers to the left of each gel represent size in hundreds of bases Jim Jose Marker 1 Marker 2 Marker 1 Jenny Joe Marker 3 Jan Jerry Julie Jim Jose Marker 2 Jenny Joe Jan Jerry Julie Jim Jose Marker 3 Jenny Joe Based on these results, which marker is most likely associated with the condition? Jan Jerry JulieQUESTION 6 To verify the is indeed inside your plasmid, you'd like to do a colony PCR. But you need primers for your reaction. Which of the following primer pairs would probably work for verifying your insert is actually present in the plasmid? 5' ATGTTTATTTTCTTATTATTTTTTACTCTCACTAGTGGTAGTGACCTTGACCGGTGCACCACTTTTGATG ATGTTCAAGCTCCTAATTACACTCAACATACTTCATCTATGAGGGGGG TTTACTATCCTGATGAAATTTT (Very long, but a bunch of nucleotides her e).... TCTTGCTTTGTTGCATGACTAGTTGTTGCAGTTGCCTCAAGGGTGCATGCTCTTGTGGTTCTTGCTGCAA GTTTGATGAGGATGACTC TGAGCCAGTTCTCAAGGGTGTCAAATTACATTACACATAA 3' Forward: 5' GGT AGT GAC CTT GAC CGG 3' Tm= 59.8 O A. Reverse: 5' CAA ATT ACA TTA CAC ATA A 3' Tm= 47.4 Forward: 5' ATG TTT ATT TTC TTA TTA TTT 3' Tm= 47.1 C O B. Reverse: 5' TAT GTG TAA TGT AAT TTG ACA CCC 3' Tm3 58.4 Forward: 5' GGT AGT GAC CTT GAC CGG 3' Tm3 59.8 OC. Reverse: 5' GTG TAA TGT AAT TTG ACA CCC TTG 3' Tm: 59.4 Forward: 5' GGT CAC TAC CAC TAG TGA GAG 3' 59.4 C O D. Reverse: 5' GTG TAA TGT AAT TTG ACA CCC TTG…
