QUESTION 1: How much KCl03reactant will be needed to produce 105.8g of tetraphosphorus decaoxide (P4010)? G: 105.8g P4010 MM: 1 mol P4010 = 287.88g P,010 1 mol KC103 = 122.45g KC103 MR:3 mol P,010 %3D 10тol кс10; СHOICES: A. 15.01g KC103 В. 150.01g КCI03 С. 1.501g КCI0, D. 0.150g KC103

General, Organic, and Biological Chemistry
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Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
Section: Chapter Questions
Problem 6.71EP: How many moles of beryllium (Be) are needed to completely react with 10.0 moles of N2 in the...
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QUESTION 1: How much KCl03reactant will be needed to produce 105.8g of tetraphosphorus
decaoxide (P4010)?
G: 105.8g P4010
MM: 1 mol P4010 = 287.88g P,010
1 mol KC103 = 122.45g KC103
MR:3 mol P,010 %3D 10тol кс10;
СHOICES:
A. 15.01g KC103
В. 150.01g КCI03
С. 1.501g КCI0,
D. 0.150g KC103
Transcribed Image Text:QUESTION 1: How much KCl03reactant will be needed to produce 105.8g of tetraphosphorus decaoxide (P4010)? G: 105.8g P4010 MM: 1 mol P4010 = 287.88g P,010 1 mol KC103 = 122.45g KC103 MR:3 mol P,010 %3D 10тol кс10; СHOICES: A. 15.01g KC103 В. 150.01g КCI03 С. 1.501g КCI0, D. 0.150g KC103
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