Q6 Figure Q6 shows a closed loop control system of a servo motor. Assuming that the input potentiometer generate a voltage of Vi, and the potentiometer on the servo motor generate a voltage of Vo. Potentiometer Differential amplifier Power Amplifier trad Potentiometer Power Figure Q6 (a) Describe the operation of control system. (b) Draw the block diagram of the control system. Servo motor Angle 00

Q6 Figure Q6 shows a closed loop control system of a servo motor. Assuming that the input potentiometer generate a voltage of Vi, and the potentiometer on the servo motor generate a voltage of Vo. Potentiometer Differential amplifier Power Amplifier trad Potentiometer Power Figure Q6 (a) Describe the operation of control system. (b) Draw the block diagram of the control system. Servo motor Angle 00

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter30: Ac Solid-state Reduced Voltage Controller

Section: Chapter Questions

Problem 1SQ: List some advantages of solid-state control.

See similar textbooks

Similar questions

1. Single phase full converter is used to control the speed of separately excited DC motors. AC supply voltage is 208 V. Motor armature and field resistance are 0.5 2 and 345 2 respectively. The field current is also controlled by a full converter and the field current is set as the maximum possible value. Motor voltage constant is 0.7 V/A-rad/sec. If firing angle is 45° and armature current is 55 A, determine the angular speed of the motor. Assume armature and field current are ripple free.
List some advantages of solid-state control.
The supply voltage to a DC motor is 160V. If the back emf Ez=155V and the armature resistance A6 is 0.250, the armature current is a) 5A b) 10A c) 15A d) 20A 1800 ro/min The frequency
The input current to a 220v, compound motor at no load is 6 A. The shunt field circuit resistance is 220 ohms; the armature resistance is 0.10 ohm and the series field resistance is 0.80 ohm. What is the SPL? A. 1153.31 W B. 1066.22 W C. 1232.54 W D. 1073.25 W
The armature circuit of a free excited direct current motor with a nominal voltage of 600 V is fed from an adjusted direct voltage source. The excitation circuit is also powered from a regulated voltage source. It is used in an application that requires motor speed adjustment. The speed of the motor at the nominal armature voltage was measured as 1600 rpm. All losses of the motor and voltage source and the effect of armature reaction are neglected. It is accepted that the engine is not saturated.Answer the questions below.a) Draw the armature and excitation circuit of the motor and write the formulas for the equivalent circuit.b) If the load moment of the motor at the nominal armature voltage is 420 Nm, then calculate the armature current and the input power of the motor.c) If the armature voltage of the motor is kept constant at 600 V and the excitation current is decreased until the speed reaches 4000 rpm, then calculate the shaft moment. Show this working area on the M = f (W) axis.
A shunt motor running on no-load takes 5 A at 200 V. The resistance of the fieldcircuit is 150 ohms and of the armature 0.1 ohm. Determine the output andefficiency of motor when the input current is 120 A at 200 V.
A DC chopper is used in regenerative braking mode of a dc series motor. The dc supply is 600 V, the duty cycle is 70%. The average value of armature current is 100 A. It is continuous and ripple free. What is the value of power feedback to the supply ?
What would be the objective of creating a prototype to control the direction of a direct current motor with an H-bridge circuit? In the world of industrial electronics, in what situations is this used?
what are the Motor control techniques can be used and the Suitable Microcontroller for above design requirements.
A 48kW, 600V, 1500 rpm separately excited dc motor is controlled by single phase semi-controlled converter. The resistance of the armature is 192 and of the field is 1450. The field circuit is controlled by a single phase fully controlled converter and its firing angle is set to 20. The AC supply voltage to the armature and field converters is a single phase 220V, 60 Hz. The voltage constant is 0.946 V/A rad/s. If the armature converter firing angle is 45 and the speed is 1200 rpm; calculate the armature current and the developed torque.
Q6/ Answer the following questions: 1. Define the DC motor drive 2. Classify the DC motor drive 3. How can be controlling on the speed of DC motor 4. Numerate the types of AC-DC converter 5. Draw the circuit of single -phase converter on separately excited DC motor 6. Write the equations the following: I. Speed(W)= II. Torque developed(Td): III. Vm=..
A hybrid stepper motor is shown in Figure Q2(b). Demonstrate how the windings of the stepper motor are excited in wave drive mode to rotate the rotor 4 steps in the counterclockwise direction. Assume that Figure Q2(b) shows the starting position (to) of the stepper motor before the windings are excited. The first step (41) is given in Table Q2(b). (Note: Transfer Table Q2(b) to the answer script; tick the correct cells in the table to show the winding excitation sequence.) (b) Table Q2(b) Clock cycle Stator pole North pole South pole i (s) t2 (s) Al A2 B1 B2 Al A2 B1 B2 Clock eyele в (s) A2 14 (s) Stator pole North pole South pole AI B1 B2 Al A2 B1 B2 stator A1 AL armature N shaft PM armature 1- amature 2 armature 2 A A2 Figure Q2(b)