Q5: 1.44 grams of a sample of marble (impure calcium carbonate) dissolved in 40 ml of 1.0 normality (N) of hydrochloric acid, then add an amount of distilled water to the resulting solution, and its volume became 100 ml, it was found that 25 ml of this resulting solution (mixture) needs 19 ml of 0.2 normality (N) NaOH solution. Calculate the normality (mole/L) of the mixture solution and then calculate the percentage of pure calcium carbonate in this sample. If you know that the molecular weight of pure calcium carbonate is 106 almol *

Q5: 1.44 grams of a sample of marble (impure calcium carbonate) dissolved in 40 ml of 1.0 normality (N) of hydrochloric acid, then add an amount of distilled water to the resulting solution, and its volume became 100 ml, it was found that 25 ml of this resulting solution (mixture) needs 19 ml of 0.2 normality (N) NaOH solution. Calculate the normality (mole/L) of the mixture solution and then calculate the percentage of pure calcium carbonate in this sample. If you know that the molecular weight of pure calcium carbonate is 106 almol *

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter4: Chemical Reactions In Solution

Section: Chapter Questions

Problem 4.117QE

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