Please help solve 10:25ull LTE OQ4. The equation relating the current in a circuit withtime is i=282.1 sin377t, where the current ismeasured in amperes and the time in seconds.Find the values of:a) The r.m.s currentb) The frequencyc) The instantenous value of the current whent=2.0msAdd a caption...> Pat+

Answered: Image /qna-images/answer/c1608e83-8041-499b-87d4-4bc8648a4cee.jpg

Answered: Q4. The equation relating the current…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Find the DC value and RMS value from this image in below. , I want the solution in a detailed picture with a white paper and a clear font. Thank you.
1. For a sinusoidal voltage trace displayed by the CRO, the time/cm switch is on 500µs/cm and the volt/cm switch is on 5V/cm. The width of one complete cycle is 4cm and peak to peak height is 5cm. Find for the waveform a) the frequency, b) the peak to peak voltage, c) the amplitude, and d) the r.m.s value
Read A 70-Vac source has the following waveform. Determine:a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angleh. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms Give the solution for J and K ONLY ans (0.99959 degrees and 63.643 ms respectively)
1. A 70-Vac source has the following waveform. Determine: a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angle h. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 54.9124°h. v(t) = 98.9949sin(20πt - 54.9124°)i. 29.0880 Vj. 108.8253°k. 66.8639 msGive the solution for K ONLY Ans: 66.8639 ms
Give the solution for J and K ONLY ans (0.99959 degrees and 63.643 ms respectively).Read A 70-Vac source has the following waveform. Determine:a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angleh. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms
2. For a sinusoidal voltage trace displayed by the CRO, the time/cm switch is on at 500µs/cm and volt/cm switch is on 5V/cm. The width of one complete cycle is 4cm and peak to peak height is 5cm. Find (a) the frequency, (b) peak to peak voltage, (c)the amplitude and (d) the rms value
A certain impedance is given by 1012° N. Does the current lead or lag the voltage, and by how many degrees? Fill in the blanks. The current the voltage by
The sinusoidal voltage trace displayed by the CRO, the time/cm switch is on 50 µs/cm and the volt/cm switch is on 20 V/cm. The width of one complete cycle is 3.6 cm and the peak to peak height is 5.8 cm. Determine the following: The frequency is = The peak to peak voltage is = The amplitude is = The R.M.S voltage is =
Ac - 100 VrmsR1 - 1kR2 - 500Rload - 1kCapacitor - 2uF Q1. How much is the capacitor voltage lagging from the AC source
For the waveform shown, determine: (a) Peak to Peak value (b) Peak value () RMS value (d) Frequency. If volts/div is 3V/div and Time/div is 25ms/div (No need to show the calculations)
Show all work please and thank you :)
A step-down chopper is to be used to supply power from a 600-V overhead wire to the commutator motor on a trolley bus. The motor may be mod- eled as a generated direct voltage in series with a resistance of 0.2 and an inductance of 25 mH. The frequency of the chopper is set at 500 Hz. (a) When the bus is stopped, what should be the ON time of the chopper to provide a motor current of 150 A? (b) What is the maximum possible generated voltage of the motor for which a current of 150 A can be supplied? (c) What is the average value of the supply current for the conditions of (a) and (b)? បទៅនឹងរស់របស (d) If the motor current is to be continuous, what should be its minimum. value?

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Q4. The equation relating the current in a circuit with time is i=282.1 sin377t, where the current is measured in amperes and the time in seconds. Find the values of: a) The r.m.s current b) The frequency c) The instantenows value of the current when t=2.0ms