Q3-) The value of the point X = 0.4 was found as in the table shown below.xo = 0Po = 1P = 2P2P3 = 8x¡ = 0.25Po1 = 2.6P12P23 = 2.4x2 = 0.5Po1.2P123 = 2.96 Po1.23 = 3.016X3 = (0.75Calculate the values of P2, P1,2 and PO,1,2 according to the table.

Name: Q3-) The value of the point X = 0.4 was found as in the table shown b
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: Q3-) The value of the point X = 0.4 was found as in the table shown below.xo = 0Po = 1P = 2P2P3 = 8x¡ = 0.25Po1 = 2.6P12P23 = 2.4x2 = 0.5Po1.2P123 = 2.96 Po1.23 = 3.016X3 = (0.75Calculate the values of P2, P1,2 and PO,1,2 according to the table.

x0=0 P0=1 x1=0.25 P1=2 P0,1=2.6 x2=0.5 P2 P1,2 P0,1,2 x3=0.75 P3=8 P2,3=2.4…

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Q3-) The value of the point X = 0.4 was found as in the table shown below. Xo =0 X = 0.25 Po = 1 P = 2 P2 P3 = 8 = 2.6 P12 P23 = 2.4 Por %3D X2 = 0,5 Po,12 X3 = 0.75 P123 = 2.96 Po1.23 = 3.016 Calculate the values of P2, P1,2 and PO,1,2 according to the table.