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- 2 place the Force 70N by Equivalent System consist of one force &couple at 1: At Supporting point (A). 2: At point (c) 0.9m 0.7m 70 NQ2: Replace the 600 Ib force of Figure below by a force through A and a couple whose forces act vertically through points B and C. 6" B A 8" 600b1.) Find the sum of the vertical forces in pounds if F1 = 30 lb at 60 deg N of W and 50 lb at 40 deg S of E. 2.) Find the resultant force if F1 = 20 N south and F2 = 30 N west.
- Q2-4- Use the graphical method to find the magnitude and direction of the resultant of these forces F-500 N 700 NQ1:- The coplanar force system shown in Figure below is subjected to a couple moment (M) and three forces. Two forces are known in magnitude and direction and shown in the Figure (150 N and 60 N). The third force is passing through the center of the semi-circle (point C). The resultant of all these forces is a single couple (750 N.m) counterclockwise. a) Determine the magnitude and dircction of the third force. b) Determine the magnitude of moment (M). c) Replace the couple (M) by two vertical equal forces acting at D and E. d) Replace the force (150 N) by and single force at D and a couple. -Radius = 5 m 150 N E 60 N Q2:- Determine all forces acting on member DEF of the frame shown in Figure below:- 150 Ib/t F D 2.0 ft 3,0 ft -3.0 m---3.0 m- B. 2.0 ft5.) If the resultant force (single equivalent force) of the given system is known to pass through point B, what must the magnitude of the applied moment couple M be? Report a positive answer if M must be counterclockwise and a negative answer if M must be clockwise. [Answer: M = -8600 N m] 650 N 30° M -3 m 300 N -5 m- 500 N Ka -2 m- B
- 2. Find the resultant couple. 2 ft 2 ft 2 ft 300 lb 150 lb -2 ft-2 ft- 30% √30⁰ 150 lb 300 lbfrom the following force table what is the direction of the resultant force E of the vectors A and B: Pullay Mas Bg PullayA 4.000 llayR PullayC Select one: a. 240 b. 350 C. 60 d. 80 e. 120B: Find the total moment of force with respect to point (O), for the two forces in next fig. 4m 2m 2m (8 degrees)
- Q1:- The coplanar force system shown in Figure below is subjected to a couple moment (M) and three forces. Two forces are known in magnitude and direction and shown in the Figure (150 N and 60 N). The third force is passing through the center of the semi-circle (point C). The resultant of all these forces is a single couple (750 N.m) counterclockwise. a) Determine the magnitude and direction of the third force. b) Determine the magnitude of moment (M). c) Replace the couple (M) by two vertical equal forces acting at D and E. d) Replace the force (150 N) by and single force at D and a couple. Radius = 5 m 150 N E M 60 NQ1:- The coplanar force system shown in Figure below is subjected to a couple moment (M) and three forces. Two forces are known in magnitude and direction and shown in the Figure (150 N and 60 N). The third force is passing through the center of the semi-circle (point C). The resultant of all these forces is a single couple (750 N.m) counterclockwise. a) Determine the magnitude and direction of the third force. b) Determine the magnitude of moment (M). c) Replace the couple (M) by two vertical equal forces acting at D and E. d) Replace the force (150 N) by and single force at D and a couple. Radius = 5 m 150 N E B M 60 N Q2:- Determine all forces acting on member DEF of the frame shown in Figure below:-Q2:- For the block shown in the figure below, the 40 lb. force is passing through points EF, the 50 Ib. force is passing throuch points JB, and the force 20 lb. is passing through point C. 1. Find the resultant force and its directions. 2. Determie the resultant moment of three forces in Figure about the x-axis, the y-axis, and the z-axis. 20 ib 50 lb 40 lb 3 dimensions in inch