Q2 : Draw the load and the bending moment diagrams that correspond to the given shear force diagrams in the figures below.[ V (kN) Figure (1) V (kN) Figure (2) 3 2 - 2 114 11 94 14 x (m) x(m) 1.4 18 -66 2.
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- Solve the preceding problem for the following data: x=1120106,y=430106,xy=780106,and=45.8:30 Test 3.pdf F1 F2 a CF3 A b a F4 D Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 = 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 = 10 kN; a = 30°, 0= 45° , B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 111.6 kN.m b) 112.6 kN.m e) - 184.6 kN.m d) - 109.6 kN.m e) - 104.1 kN.m 0 None of them 21 What is the resultant moment of the five forces acting on the rod about point B? a) -95.8 KN.m b) 42.7 kN.m c) 80.9 kN.m d) 10.9 kN.m e) 51.8 kN.m ) None of them 31 What is the resultant moment of the five forces acting on the rod about point C? b) - 21.1 kN.m e) 17.4 kN.m d) - 16.5 kN.m e) 15.6 kN.m ) None of them a) 32.6 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 37.6 kN.m b) 73.8 kN.m c) 71.6 kN.m d) 52.1 kN.m e) 21.1 kN.m ) None of them 5] What is the moment of the force F2 about point E? a) 90.7 kN.m b) - 88.1 kN.m c) 54.6 kN.m d) 103.1 kN.m e) 100.7 kN.m ) None…Review Learning Goal: To use the vector cross product to calculate the moment produced by a force, or forces, about a specified point on a member. Part A - Moment due to a force specified by magnitude and endpoints The moment of a force F about the moment axis passing through O and perpendicular to the plane containing O and F can be expressed using the vector cross product, Mo =r x F. In a properly constructed Cartesian coordinate system, the vector cross product can be calculated using a matrix determinant: As shown, a member is fixed at the origin, point O, and has an applied force F, the tension in the rope, applied at the free end, point B. (Figure 1) The force has magnitude F = 180 N and is directed as shown. The dimensions are ¤1 = 0.350 m, x2 = 1.90 m, y1 = 2.30 m, and z1 = 1.20 m. What is the moment about the origin due to the applied force F? i j M =rx F =|rz k Express the individual components of the Cartesian vector to three significant figures, separated by commas. ry F F,…
- The dimensions are of the graph are d1 = 7 cm , L1 = 6 m , d2 = 4.2 cm , and L2 = 5 m with applied loads F1 = 130 kN and F2 = 60 kN . The modulus of elasticity is E = 80 GPa . Use the following steps to find the deflection at point D. Point B is halfway between points A and C. What is the reaction force at A? Let a positive reaction force be to the right.F = F cos # F = F + F F F sin 8. # tan Exampie (1):Find the two components of the force (100 X) if: 0 = 30", 120 270° as shown in figure. F = 100 N F = 100 N 6=30 0 =120° 0 =270 0 = 30 0 =60 F = 100 N lution:tol F = Fe F= F + F COs # F F sin a. # tan Example (L):Find the two components of the force (100 X) if: 0 = 30, 120 270° as shown in figure. F = 100 N F = 100 N 6%330 6 =120° 0 =270° 0 = 300 0 60 F = 100 N ution:
- In the graph the force versus displacement of a spring is given (the spring is shown in a separate figure--see below). The x-axis range is ±2 cm. The y-axis range is tFs, where Fs = 220 N. How much work does the spring do on the block (the mass "m") when the block moves from x₁ = 7.6 cm to 4.3 cm? W J y F. X -1.5 -0.5 0 10.5 1 1.5 -F How much work does the spring do on the block (the mass "m") when the block moves from x; = 7.6 cm to -7.6 cm? W = Question Help: Read Submit Question m1) A cylindrical rod of constant shear modulus, G is of length L and located between z=0 and z=L. It has a polar moment of inertia given by J=(Jo)/(1-Z/L) and t=-sin(πZ/2L)where Jo is a constant.The boundary conditions are dΦ(o)/dz =0 AND Φ(L)=0 Find Φ(z) and graph (1/GJo)Φ(Z), and (1/GJo)(dΦ(Z)/dz) ?2 B 2
- The figure shows a cantilevered beam, subjected to a uniformly distributed (rectangular) 40 N/m force along the section DE, a 50 N point force at point C, and a 200 Nm couple moment. a. Write the shear-force and bending-moment equations as a function of distance, x, measured from the leftmost point, A, for the entire beam. b. Using your shear-force and bending-moment equations, calculate the shear force and bending moment at x = 2 m and x = 5 m. 200 N·m A 2.5 m 50 N CV D 1 m 40 N/m ↓↓↓ 2.5 m E B 2 mA rectangular plate ABCD with base L = 283 mm and height H = 376 mm experiences the deformation illustrated below, resulting in the deformed plate shown by dotted lines. Determine the average shear strain y at the corner C when a = 3 mm, b = 4 mm, c = 4 mm, d = 4 mm, e = 3 mm and f = 3 mm. Assume small deformations. %Matlab input: L = 283; H = 376; a = 3; b = 4; C = 4; d = 4; e = 3; f = 3: y d B C H b A a L:Q81 The moment M for the force the figure shown below is 250 N 153 -200 mm 30 mm 46.5 N.M O 46.6 N.M O 46.4N. M of L is