Q1) Write 8086 program to zeroing the number (-4 h) using shift instruction? Q2) Write 8086 program to execute the following :- X=5 Where I=0 X=X+1 Where I=1 X=X+2 Where I=2 X=X+3 Where I=3
Q: Assume the following initial values of registers r1-r5: re= 0x0 r1= 0x0 r2= 0x0000000A r3=…
A: Please check the step 2 for solution
Q: 7.3.5 - What bit positions (15 to 0) in R4 will be cleared when the following instruction is…
A: Bit operation will do and operation Then r4 contains 000000000h then And operation with #256 means…
Q: 4- Assume BX= 6A83h, AH= 89h, DX= 5678h, SI= 1234h. Select an OR instruction that will: (a) OR BL…
A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: 2. write 8086 program to copy content of Ax=299fh, BI=87h into memory location A222AH in Es segment…
A: Data copy/ Transfer Instruction 1) MOV- Move Transfers data from 1 register/memory to another…
Q: Read the following code carefully to answer what it does: START: MOV SI, 0300 MOV DI, 0302 MOV AX,…
A: Here is the solution:
Q: 3- If AX=(BA78). Write a program that finds the value of AX after executing each instruction in…
A: Given AX = (BA78) To write a program that finds the value of AX after executing each…
Q: 7-lf we assume we place the following MIPS code starting at location 8000 in memory, what is the…
A: 1) SLT $t2 $zero $t0 Binary: 00000000000010000101000000101010 Hex: 0x0008502a 2) BNE $t2 $zero…
Q: onsider the code sequence below lw $t1, 4($t0) add $s2, $t1, $t2 lw $t3, 16($t0) add $s3,…
A: Memory operands - Data transfer command: A command to move data to and from memory Registered…
Q: 2. Study this program then answer the questions that follow: MOV DX , 1234 H MOV BX, 3099 H MOV AL,…
A: 1)here , the given code is of addition operation. Where two numbers are being added using AX…
Q: Let R15=0x0000 00FF. The contents of the memory location at an address equal to the last 5 digits of…
A: R15 =0x0000 00FF. The contents of the memory location at an adress equal to the last digits of your…
Q: Q1: what is the addressing mode for the following instructions: 1. SUB A,B,C 2. OR A,B 3. ADD R1 4.…
A: Instructions Addressing Mode Explanation 1. SUB A,B,C Implied addressing mode The SUB is a…
Q: 3. Assume the following 64b register contents: x5 O×0000000OODEADFAD, x6 = 0×BADBEEF011223344 For…
A: Answer is given below .
Q: A - Mention how do the following instructions differ 1- NEG & NOT 2- DIV & IDIV 3- AND & TEST 4- CMP…
A: A microprocessor is a computer processor that incorporates the functions of a central…
Q: 7.3.1 - What bit positions (7 to 0) in R4 will be cleared when the following instruction is…
A: Dear Student , bic.b src,dst - performs the following operation - not(src) and dst - and stores…
Q: Q/2 Excute the following instruction using zero address instruction? X=(A+B)* (C+D)/G+H*I * Your…
A: Expression: X = (A+B)*(C+D)/G+H*IPostfixed : X = AB+CD+*HI*G+/TOP means top of stackM[X] is any…
Q: 14- Change the content of memory location [300h] to FFh without using MOV instruction. Use just one…
A: Algorithm : Move 300h into CX register Move CX into DS segment (now we are in 300h data segment)…
Q: Q:find the actual address for the ..il following instruction assume X=38 and R index=DDCE8 hex LOAD…
A: Given: X = 38 Ri = DCE8
Q: 3. What is the result of executing the following instruction sequence? SUB AL , CL DAS Assume that…
A: We have 2 assembly instructions and we need to find the result of these commands. The instructions…
Q: Q:find the actual address for the following instruction assume X= (27)hex and R index=DBC9 LOAD…
A: Question:
Q: What will be the value of the Carry flag after each of the following instruction sequences has…
A: Given that: To find out what will be value of the carry flag after each of the following instruction…
Q: 14. Assume that AL= 1010 1111, CF=0, Here is how the rotate instruction affect AL and CF. After ROL…
A: After ROL AL, 1AL= 1101 1111, CF=1, After ROR AL, 1AL =1101 0111, CF=1, After RCL AL, 1AL = 0101…
Q: What is the result of executing the following instruction sequence? MOV AX, 9457H MOV BX, 2478H DEC…
A: Given instruction sequence- MOV AX, 9457H MOV BX, 2478H DEC BL SUB AL, BL SBB AH, BH NEG BX HLT
Q: Answer the following short questions a) Explain what happens when the following instruction…
A: a)LAHF : copies flag register's lower byte into AH registerMOV[BX+DI],AH : this will move the value…
Q: 10- Execute each instruction below and show the result of the registers. MOV AX, 453ЕН MOV BX, 1234H…
A: According to the information given:- We have to find the register values of after execution.
Q: Assume the following register contents: $t0 = 0x01234567, $t1 = 0x56781234. Set back to these values…
A: The value of $t1, $t2, $t3, $t4 after the above instructions are given below
Q: 7.3.2 - What bit positions (7 to 0) in R4 will be set when the following instruction is executed?…
A: From the given data, The instruction is bis.b #00000011b, R4 where R4 is an 8-bit register. and bis…
Q: 7.3.4 - What bit positions (7 to 0) in R4 will be set when the following instruction is executed?…
A: 7.3.4 - What bit positions (7 to 0) in R4 will be set when the following instruction is executed?…
Q: 3- Suppose AL is initially equal to 11100011 binary and then we OR it with 00000100. Write a code to…
A: According to the information given:- We have to write code and execute the instruction and the…
Q: 1-In a multi-byte addition program , when must you use the ADD instruction ? when must you use the…
A: The solution for the above-given question is given below:
Q: (ii) What is the content of register AX after executing the following instruction? mov AX, [0x208]…
A:
Q: B- Fill the blank with the correct word to give a meaningful to a 8086 statements. 1-The convention…
A: According to the Bartleby guideline, we are supposed to answer only the first 3 fill in the blank…
Q: Q:find the actual address for the following instruction assume X=38 and Rindex=DCE8 LOAD X(Ri), A…
A: Given, R index = DCE8 Value of X = 38 The above value is the offset value which is an integer value…
Q: 1-a: The content of AR at timing T1 is . when an ISZ instruction fetched from .memory and executed…
A: Actually, AR is a Address Register.
Q: 13.12, The x86 architecture includes an instruction called Decimal Adjust after Addition (DAA). DAA…
A: Here is the answer with an explanation:-
Q: * H/W At a certain time, the simple computer registers contents the following data: PC = 1FFH, AR =…
A:
Q: Read the following code carefully to answer what it does: START: MOV SI, 0300 MOV DI, 0302 MOV AX,…
A: We need to find the correct option regarding the given assembly code.
Q: Q4/ A- write a program to count number of one's & zero's in a number stored at 0200:0010, use rotate…
A: Answer is given below .
Q: 3. Assume $s1 = 0xefbcad97, $s2 = 0x6521fedc, calculate and $s0,$s1,$s2 or $s0,$s1,$s2 xor…
A: Here is the answer:-
Q: b-) Convert the following instruction to machine code in decimal. (No need to convert it to binary)…
A: Below is the correct answer to above question. I hope this will meet your requirements.....
Q: 2.39 [5] Write the MIPS assembly code that creates the 32-bit constant 0010 00 0000 0001 0100 1001…
A:
Q: 8.1 Give the sequence of three-address code instructions corresponding to each of the follow- ing…
A: NOTE: As per bartleby guideliness for multiple question, we are supposed to answer only first…
Q: What will be the values of the specified registers and flags after the execution of the following…
A: Here is the explanation.
Q: 19. Write the code that performs the following computation using the STACK instruction PUSH and POP…
A: Steps to calculate X: PUSH P, PUSH Q, SUB, POP C,…
Q: 2. Study this program then answer the questions that follow: MOV DX, 1234 H MOV BX , 3099 H MOV AL,…
A: The registers AX,BX,CX,DX stores the 16 bit values. The AL and AH are the registers that store the…
Q: B- Write a single instruction that loads AX from address 0200 H and DS from address 0202H.
A:
Q: What is the result of the following instruction sequence? mov dl, 40 shr dl, 1 (Assume decimal…
A: mov instruction moves the value into a register shr is for logical shift right operation In shr,…
Q: the maximum mode, the status signals S₁, S₂ and S3 are controlled by the bus controller. 3. HLDA is…
A: You can input data of size 16-bit through the fixed port.true
Q: What are contents of R5 after execution to each of the following instruction? (Assume R2 contains…
A: We have different Arithmetic and logical instructions here, we have to find out the contents of R5.
Q: 9- Choose an instruction that subtracts 1 from register BX= 33BAH 10- Write a code to execute SBB…
A: Note: As per our guidelines, we are supposed to answer only one question. Kindly repost other…
Q: 1. What is the result of executing the following instruction sequence ? ADD AL, BL DAA Assume that…
A: Assembly instructions are machine language instructions which is used to perform operations .…
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- CAN ONLY USE X86 LANGUAGE FUNDAMENTALS REVERSE 8 BYTES NUMBER WITH MOV ONLY: We have an 8 bytes width number, so we save the lower bytes in EAX and higher bytes in EDX: for example number 1234567812131415h will be saved like EAX = 12131415h, EDX = 12345678h. Write a general-purpose program that is able to reverses any number 8 bytes width number that its least significant bytes are in EAX and its most significant bytes are saved in EDX . Note: Reverse means that our sample number becomes: EAX=78563412h and EDX = 15141312h. Consider this sample call: .data EAX: 12131415h EDX: 12345678h NO HIGH LEVEL ASSEMBLY PROGRAMMING. NO SEGMENTS, GLOBAL. Please explain using MOV5. Write an assembly language program that inputs the number of a student from the keyboard and after the entry, it displays the number at the centre of the text screen in vertical manner. For example, if you enter your student number as 87138 it will be displayed at the centre of the monitor in the following way: 8 7 1 3 8 Hints: INT 21H, AH= 0AH inputs a string of data from the keyboard. The interrupt requires that the offset address of the buffer is in DX. INT 21H, AH= 02 outputs a character to the monitor and assumes the character in DL (ASCII). INT 10H, AH= 02 sets cursor location and assumes row in DH and column in DL.Project Summary: Write an Intel 8086 Assembly program that reads N numbers as Strings, convert them into variable sized Integer numbers, and then print the summation and average of the numbers. The program should allow the user to decide the size of the input number itself (assume integers in format but with variable size). Detailed Description: - Have the program prompt the user to input N and the size of the number then request inputting the first number, then the second and so on until N numbers are input. - Your code should allow users to select the size of the numbers, for example you can have integers with size of 1 Byte each, or you can make them 10 Bytes large. - Validation: Your code should make sure user inputs Decimal numbers only, and with predetermined size only. When a user inputs a wrong value, your code should print an error message that explains it, and then gives the user another chance to input it correctly. - When the user presses Enter, your code should read the…
- Q2/Write a program with a specific programming language to insert a user program into memory and allocate locations for it using Reg Fence once and use relocatio again e 1:41 Q3/Apply that if the program is 5kb, 22kb, or 40kb, what will happen in the implementation of C ++ language 2 1:41Below C-code has a for loop which will repeat 1000 times of the operation. This code will be running on very simple machine. Change the code to reduce the number of branch instructions. You can have up to 5 lines (statements) within the for loop. What is the number of branch operations before and after? for (i=0; i<1000; i++){ y[i] = w * x[i] + b[i]; }38. Implement the following expression in assembly language, using 32-bit integers (you may modify any registers you wish): eax = -dword1 + (edx - ecx) + 1 You can use this data definition for testing your code: dword1 DWORD 10h 39. se the following data declarations to write an assembly language loop that copies the string from source to target. Use indexed addressing with EDI, and use the LOOP instruction source BYTE "String to be copied",0 target BYTE SIZEOF source DUP(0),0
- Write a sequence of statements that display a subroutine’s return address. Hint: the esp register points to the return address stored on the call stack. You can call procedure WriteHex. This can be solved in 2 lines of code. The following exercise can be solved using either 32-bit or 64-bit code. Assembly languageCourse: Assembly Language Write an assembly program that lets the user to type some text, consisting of wordsseparated by blanks, ending with carriage return, and display the text in the same word orderas entered, but with the letters in each word reversed. For example, “this is a test” becomes“siht si a tset”. Note: code in 8086 processorElectrical Engineering Consider a function called Vocals. This function has as parameter the starting address of a string of characters. The function calculates the number of times the 'a' character appears (in lowercase) in the string. In case of passing the mull string the function returns the value -1. In case the string does not have any 'a', the function returns 0. It is requested: 1. Program using the assembler 8086 the code of the Vocal function 2. Program using the ARM assembler the code of the Vocal function
- Write a code in sim8085 for the following problem: The pressure of two boilers is monitored and controlled by a microcomputer works based on microprocessor programming. A set of 6 readings of first boiler, recorded by six pressure sensors, which are stored in the memory location starting from 2050H. A corresponding set of 6 reading from the second boiler is stored at the memory location starting from 2060H. Each reading from the first set is expected to be higher than the corresponding position in the second set of readings. Write an 8085 sequence to check whether the first set of reading is higher than the second one or not. If all the readings of first set is higher than the second set, store 00 in the ‘D’ register. If any one of the readings is lower than the corresponding reading of second set, stop the process and store FF in the register ‘D’. Data (H): First set: 78, 89, 6A, 80, 90, 85 Second Set:71, 78, 65, 89, 56, 75Here function f returns the results through address passing. Assuming c is a global complex number defined in main.c, please implement f.h by selecting line numbers from the following lines in correct order. Remember each blank can hold just one line number. 1 #include 2 #include 3 #include "g.h" 4 #include "f.h" 5 extern c_t c; 6 c tc; 7 c_t g(c_t, c_t): 8 c_t g(c_t a, c_t b){ 9 c_tre, 10 c_t re1, re2; 11 else { f(&re1, n-1); f(&re2, n-2); *re = g(re1, re2); } 12 f.o: f.h g.h 13 f(&re, 10); 14 f: main.o f.o g.o дсс -c f.c gcc -c g.c gcc -c main.c gcc -o f main.o f.o g.o -Im 15 16 17 18 19 g.o: g.h 20 if (n <= 1) *re = c; 21 int main(void) 22 main.o: f.h g.h 23 printf("%f\n", sqrt(re.x - re.y)); 24. rox 24 re.x = a.x"b.x - a.y*b.y; 25 re.y = a.x*b.y + b.x*a.y; 26 return 1- 27 return re: 13; 28 scanf("%lf%lf", &c.x, &c.y): 29 typedef struct { double x, y; } c_t; 30 void f(c_t *, int); 31 void f(c_t *re, int n) { 32 }Write program segments that perform the operation C C+ A x B using each of the instruction classes indicated in Exercise 1 above. Assume that A, B, and C are memory 3. addresses. lleuing data Lin the