Q1: The following test results are obtained on a 7,500-line V alternator: O.C.V.: 3,100 4,900 6,600 7,500 8,300 Field current (A): 16 25 37.5 50 70 A field current of 20 A is found necessary to circulate full-load current on short-circuit of the armature. Calculate by (i) the ampere-turn method and (ii) the synchronous impedance method the full-load regulation at 0.8 p.f. (lag). Armature resistance is 2 ohm and leakage reactance is 2 ohm.

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter31: Three-phase Alternators
Section: Chapter Questions
Problem 1RQ: What conditions must be met before two alternators can be paralleled together?
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Q1: The following test results are obtained
on a 7,500-line V alternator: O.C.V.: 3,100
4,900 6,600 7,500 8,300 Field current (A):
16 25 37.5 50 70 A field current of 20 A is
found necessary to circulate full-load
current on short-circuit of the armature.
Calculate by (i) the ampere-turn method
and (ii) the synchronous impedance method
the full-load regulation at 0.8 p.f. (lag).
Armature resistance is 2 ohm and leakage
reactance is 2 ohm.
Transcribed Image Text:Q1: The following test results are obtained on a 7,500-line V alternator: O.C.V.: 3,100 4,900 6,600 7,500 8,300 Field current (A): 16 25 37.5 50 70 A field current of 20 A is found necessary to circulate full-load current on short-circuit of the armature. Calculate by (i) the ampere-turn method and (ii) the synchronous impedance method the full-load regulation at 0.8 p.f. (lag). Armature resistance is 2 ohm and leakage reactance is 2 ohm.
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