Q1: Find the resultant force and the component force F for the system shown below (fig 1) using parallelogram law, (Assume a value for force P and angle B). (0=35°)
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- Q1: Find the resultant force and the component force F for the system shown below (fig 1) using parallelogram law, (Assume a value for force P and angle B) 0 =35° Fig 1Example ( 2-1) : The ring in the figure below is subjected to two forces ( F1) and ( F2). Determine the magnitude and direction of the resultant force. 10° F, = 150 N F = 100 N %3D 15° Solution : Parallelogram Law. The parallelogram is formed by drawing a line from the head of F1 that is parallel to F2 , and another line from the head of F2 that is parallel to F1 , the resultant force FR extends to where these lines intersect at point A. The two unknowns are the magnitude of ( FR) and the angle ( 0) (theta).Problem 4 From the figure, w1 =13kN/m, w2=10kN/m, F1 =7kN 1. Find the resultant of the forces 2. Find the location of the resultant from point B. 7m 4m 2m
- Question #1: Determine a single-force equipollent system for the figure below. Give resultant force magnitude and position. The plane of the shaded triangle is the xy plane and the forces are all normal to it. ZA 35 60 N 79 2m X 2 m 100 N 80 N 2 m (xy is plane of triangle; forces are normal to it.)w1 Problem 4 From the figure, wi =15KN/m, w2=12kN/m, F1 =7kN 1. Find the resultant of the forces 2. Find the location of the resultant from point B. to 7m 4m 2mProblem #3: From the given set of non-concurrent forces shown in the figure, determine the Resultant force which could represent them. Figure: Q=20KN IC. T=40KN P=25KN: Im CB W=50KN
- Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the %3D moment that the force, F, exerts .about the point A F A. M = -1042 O M = -1055 M = -1046 M = -1050 OQ) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the moment that the force, F, exerts .about the point A F C A M = -1042 M = -1055 M = -1050 M = -1046A weightless rectangular bar BDC is loaded as shown below. There is a smooth pin at point C, a 100 N force at point D and a cable at point B. The bar and all forces are in the plane of the page (2D case). A F = 100 N 2 m 50° C 2 m 2 m 4 m a) Write the 100 N force using polar vector representation: F = |F| N@ angle 0 CCW from +x to the right. Calculate the angle theta in degrees. b) Calculate the moment of the 100 N force about point C. Give your answer in N-m (newton- meter). c) What should the direction of the 100 N force be to produce a zero moment about point B? Calculate and report the smallest angle in degrees CCW from +x to the right (angle in standard position). d) What should the direction of the 100 N force be to produce a zero moment about point A? Calculate and report the smallest angle in degrees CCW from +x to the right (angle in standard position).
- H.W.pdf > Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 0, = 35° and 02 = 0, = 20°. Calculate the moment that the force, F, exerts about the point A. B CGO 321 3 in F1 F2 a F3 A d F4 F5 Consider the following values: - a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 7 kN; F2 = 8 kN; F3 = 9 kN; F4 = 10 kN; F5 = 11 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 158 kN.m b) 127 kN.m c) 146 kN.m d) - 103 kN.m e) 241 kN.m f) - 171 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 98.8 kN.m b) - 291.7 kN.m c) 311.6 kN.m d) – 264.6 kN.m e) 354.2 kN.m f) - 242.5 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) - 141.1 kN.m c) 14.6 kN.m d) - 272.1 kN.m e) 174.1 kN.m f) - 315.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 117.8 kN.m b) 82.7 kN.m c) 121.9 kN.m d) - 259.9 kN.m e) 127.1 kN.m f) 300.1 kN.m Activate 5] What is the moment of the force F2 about point E? a) 151.7 kN.m b) 118.1 kN.m c) 214.6 kN.m d) 158.6 kN.m e) 101.1 kN.m loA ball (B) is stopped on inclined surface 30° with horizontal by a horizontal force p=100N. a. Resolve the force P in two rectangular components parallel and normal to the inclined surface. b. If another force T=50 N pull the ball in direction parallel to the inclined surface , replace this pair of forces by single force. c. Find the resultant of single force above.