Q.12: The non-sinusoidal applied voltage for the 1C circuit shown is: (e-=5+4sin1000t+2sin3000t) V. 1. Derive the equation of currents (i) & (ic). 2. Find the total power consumed in the circuit? (Ans.: i=1+0.73sin(1000t-24°) A, ic=0.09sin(1000t+155.8°)A & Pr=6.33W) :-J180 SJ22

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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1L
Q.12: The non-sinusoidal applied voltage for the
circuit shown is: (e,=5+4sin1000t+2sin3000t) V.
1. Derive the equation of currents (i) & (ic).
2. Find the total power consumed in the circuit?
(Ans.: iT=1+0.73sin(1000t-24°) A, İc=0.09sin(1000t+155.8°)A & P;=6.33W)
eT
1C
-J180 J22
Transcribed Image Text:1T 1L Q.12: The non-sinusoidal applied voltage for the circuit shown is: (e,=5+4sin1000t+2sin3000t) V. 1. Derive the equation of currents (i) & (ic). 2. Find the total power consumed in the circuit? (Ans.: iT=1+0.73sin(1000t-24°) A, İc=0.09sin(1000t+155.8°)A & P;=6.33W) eT 1C -J180 J22
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