Q-2-A Particle maves ina straight line so that aftert sec. it is Sm.from a fixed Paint O an the line,where s=£+ 3+². Finod;+3+2. Find:1) The acceleration when t=1,t=2, t=32)) The average acceleration betwween t=L and t3.

Name: Q-2-A Particle maves ina straight line so that aftert sec. it is Sm.f
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Q-2-A Particle maves ina straight line so that aftert sec. it is Sm.from a fixed Paint O an the line,where s=£+ 3+². Finod;+3+2. Find:1) The acceleration when t=1,t=2, t=32)) The average acceleration betwween t=L and t3.

The displacement is s=t4+3t2 The velocity of the particle as function of time is…

Science

Physics

Q-2-A Particle maves in a Straight line so that aftert t sec. it is sm. from a fixed Paint o an the line .4 where S=£+ 3+². Find; 1) The acceleration whent=1,t=2,t=3 2) The average acceleration betweent=l andt=3

Q-2-A Particle maves in a Straight line so that aftert t sec. it is sm. from a fixed Paint o an the line .4 where S=£+ 3+². Find; 1) The acceleration whent=1,t=2,t=3 2) The average acceleration betweent=l andt=3

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 80AP: A particle travels m a circular orbit of radius 10 m. Its speed is changing at a rate of 15.0m/s2 at...

See similar textbooks

Similar questions

A football player runs from his own goal line to the opposing teams goal line, returning to the fifty-yard line, all in 18.0 s. Calculate (a) his average speed, and (b) the magnitude of his average velocity. (Sec Section 2.2)
Clay Matthews, a linebacker for the Green Bay Packers, can reach a speed of 10.0 m/s. At the start of a play, Matthews runs downfield at 45 with respect to the 50-yard line and covers 8.0 m in 1 s. He then fins straight down the field at 90 with respect to the 50-yard line for 12 m, with an elapsed time of 1.2 s. (a) What is Matthews’ final displacement from the start of the play? (b) What is his average velocity?
A seagull can fly at a velocity of 9.00 m/s in still air. (a) If it takes the bird 20.0 mm to travel 6.00 kin straight into an oncoming wind, what is the velocity of the wind? (b) If the bird turns around and flies with the wind, how long will it take the bird to return 6.00 km?
Between t=0 and t=t0 , a rocket moves straight upward with an acceleration given by a(t)=ABt1/2 , where A and B are constants. (a) If x is in meters and t is in seconds, what are the units of A and B ? (b) If the rocket starts from rest, how does the velocity vary between t=0 and t=t0 ? (c) If its initial position is zero, what is the rocket’s position as a function of time during this same time Interval?
Q-2- A Particle maves in a Straight line so that after t sec. it is sm. from a fixed Paint o an the line, where s=±*+ 3+². Finod; + 3 t². Find ; 1) The acceleration when t=1, t=2, t=3 2)) The average acceleration between t=l and t=3
4. A runner goes North for 3 km, then turns and heads South for 5 km, then turns North gogin gint dops not TU 3 d sit bno 35MATZI0 at dtod aya took. for 4 km. Draw a diagram in part "a" to show the path the 29notzib 1ot noitibbo- b. What DISPLACEMENT did the runner a. What DISTANCE did the runner go? mu1osiT nos1opority9 art onizhave at the end of the trip? (length and direction) .m0L ot dtno nat ml 010t dtuo2 aboord girda sziuɔ A I loot toɔ art dtoq sit worlz ot "o" troq ni monpoib D wond Sanop sɔnotaib alt 2ow tordW.D Stasmscplgaib sit 2ow tordW.d (anop noitasnib bno dtpnsl) 5. A hoverboard rider goes straight down Arkansas Avenue for 2 miles, then turns left and goes straight for 3 miles, then turns right and goes 1 mile before stopping. Draw a diagram in part "a" to show the path the hoverboard rider took. 1stam 08 1b. What. Whet srltono not tripionte ow bno nippo tdoin have at the end of the trip? (length and a. What DISTANCE did the rider go? PLACEMENT did the ridert2ol A S Which…
Problem 3 A volleyball is thrown with an initial velocity at 30 m/s at an angle 40° above the horizontal. Find the following: 1. Sketch the problem and label the important parts 2. Total time flight 3. Maximum height reached 4. Horizontal distance from the starting point will the volleyball attains its original level. (1) Given and Unknown Idgi to omis letor o bail coe
Physics 30S Science & Technology 2240 Grant Ave. Winnipeg. MB R2C IL6 Shaflesbury High School Motion: Speed/Velocity & Acceleration Ad V = At a = Average Velocity, 1. A man jogs 5.0 km (5000 m) in 27 minutes. a) What is the time interval (At) in seconds? b) Calculate his average speed in metres per second (m/s). Average Acceleration, At 2. An object has a position of 13 metres west. 5.0 seconds later it's at 7 metres east. a) What was the initial position? b) What was the change of position or displacement (Ad)? c) What was the average velocity? 3. A world class sprinter runs 100.0 m in 8.90 s. What was his average speed? 4. A hiker gets lost in a forest. He walks half-way around a circle with a radius of 2.1 km in 2.0 hours. a) What distance did he walk? b) What was his average speed? c) What was his displacement? d) What was his average velocity? WE S C-2rr 5. A car has an average highway speed of 90 km/h or 25 m/s. At this speed; how long will it take to drive to Kenora which is 190…
4. A particle start from rest and moves in straight line with an acceleration of a- (2t-6) m/s, where t is in seconds. What is the particles velocity when t-és (V(6) - Om/s ), and what is its position when t- 11s?(80.7 m)
Y:OY I | %A. N a rE,VK/s a “.lzain IQ docs.google.com/forms مطلوب A 4 نقاط The position of a particle is defined by x=2t3-18t2+48t-16, where x in m and t in s. Determined 1) when the velocity is zero, 2) the velocity, the acceleration and the total * .distance traveled at t=2s 8, 40, 12, 24 others 8, -40, -12, 24 8, -40, -12, -12 O 8, 40, -12, 12 O 4 نقاط A particle A is accelerate from X=0 with zero initial velocity at a=0.8/v2 + 49, where a, v in m/s and m/s respectively. Determine 1) the position of A at any time. 2) the speed of A at any time.
asa Ys beogl take this car to reach a velocity of 30 m/s east? How far will the car travel during this time? 3m152 4大号 At=? 7. An object's velocity curing a 10 second time interval is shown by the graph below: Velocity (m's) ou ml gnin AS Teboo Sni lovu 3- MYE 1+ Time (seconds) 10 s lieiio abrgAE w.un 0.0 i abn od to boor lacil 1 3 5 -1+ fooitelae ab -2+ Determine the object's total distance traveled and displacement. Show all work. 大-10sec AK-Xott'sat? よニ105cc Ax-o(0)t5 d=17.sm Ax-? bs 1291 mo do AA noitenfooon or onims Vo =omIs BJAt1= 0, the object's position is x = 2 m. Find the object's position at t= 2, t = 4, t = 7, andt = 10. Show all work. Saboo 01 o iloe l wol d 8. Is it possible to move with constant speed but not constant velocity? Explain your answer. 1es because velocity isaspecel of me obiect with Specifi cation of it's direct ion, boog ad A -to noilol hy the College Board
2.) A subway train starts from rest at a station and accelerates at a rate of 2.50 mls for 15.9b seconds. H then runs at a constant specd of 35 seconds and then slows down at a rate of 4.50 ml s² until it sto ps at the next station? Q) what is the speed of the frain to finish tħ before It starts slo wing down? Given: Solution: Vi: o mis a: 2.50 m Is² At:15.90 seconds. Vp: (o mls) + (2.50 mls²)( 15.90 s) : 39.75 mls Requined: Equation: Vf = Vi t a At %3D b.) How long did it take the train to finish the trip from one station to the other ? Given: Vf= 39.75 mls t1= 15.90 s solution 0: 39.75 mls - 4.50 ml S*ts : 4.50 m Is² to=89.75 mls = to: 39.75 m ls 4.50 mlsz : 8.83s Requinud: Total time (t) t: s t 8.83 s 15.90s 35S 59.73s Equation: t: tit tz t t3 to: Vf.