For (b) and (c) upload chart and table images. PXV=RXTwhere v=specificvolumeR= idealgasconstantfwater=461.5 J/kg.KThereforeRXTV=P461.5×623v=15×106v=0.01917 m³/kg(b) Usingthgeneralized bmpressibilityhartAt P=15MPaandT=350°C, usingompressiblitylthespecificvolumeis,v=0.01246 m³/kg(c) UsingthesteamtableAt P=15MPaandT=350°C, using steamtablethespecificvolumeis,v=0.01148 m³/kgTheerrorinthespecificvolumeforthefirsttwocase:Case (a) Theerrorinthespecific volumeis,Va-Veа%Error=×100where v=thespecific volume incase (a)v=thespecificvolumeincase (c)0.01917-0.01148%Error=×1000.01148% Error=67%

Answered: Image /qna-images/answer/376106bb-1256-4ddb-afef-d84261a025f3.jpg

PXV=RXT where v=specificvolume R idealgasconstantfwater-461.5 J/kg.K Therefore V= RXT P 461.5×623 V= 15×106 v=0.01917 m³/kg (b) Usingthgeneralized bmpressibilityhart At P=15MPaandT=350°C, usingompressiblityl thespecificvolumeis, v=0.01246 m³/kg (c) Usingthesteantable At P 15 MPaandT=350°C, usingsteamtable thespecificvolumeis, |v= =0.01148 m³/kg Theerrorinthespecific volumeforthefirsttwocase: Case (a) Theerrorinthespecific volumeis, V-V a C %Error= x100 V C where v=thespecific volume incase (a) v=thespecificvolume incase (c) 0.01917 0.01148 %Error= 0.01148 % Error=67% x100

PXV=RXT where v=specificvolume R idealgasconstantfwater-461.5 J/kg.K Therefore V= RXT P 461.5×623 V= 15×106 v=0.01917 m³/kg (b) Usingthgeneralized bmpressibilityhart At P=15MPaandT=350°C, usingompressiblityl thespecificvolumeis, v=0.01246 m³/kg (c) Usingthesteantable At P 15 MPaandT=350°C, usingsteamtable thespecificvolumeis, |v= =0.01148 m³/kg Theerrorinthespecific volumeforthefirsttwocase: Case (a) Theerrorinthespecific volumeis, V-V a C %Error= x100 V C where v=thespecific volume incase (a) v=thespecificvolume incase (c) 0.01917 0.01148 %Error= 0.01148 % Error=67% x100

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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