public static void find (int [] arr1, int [] arr2, int start)
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![1(6).png
public class output{
public static void find (int (] arr1, int [] arr2, int start)
{
int x=0, y=0,m=0;
for(int i = 0;i« arr1.length;i++)
if (arr1[i] == start)
x++;
for (int j = 0;j< arr2.length;j++)
if (arr2[j] == start)
y++;
for(int k
{
if ((arr2[k] == start) && (arri[k] == start))
0;k< arr2.length;k++)
%3D
3D
m++;
int R = (x+y) - m;
System.out.println (R);
} // end of find method
public static void main(String [] args) {
int [] arri = {10,10,30};
int [] arr2 =
find (arr1, arr2, 10);
{5,10,5};
}// end of main
}// end of class
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- Question 37 public static void main(String[] args) { Dog[] dogs = { new Dog(), new Dog()}; for(int i = 0; i >>"+decision()); } class Counter { private static int count; public static void inc() { count++;} public static int getCount() {return count;} } class Dog extends Counter{ public Dog(){} public void wo(){inc();} } class Cat extends Counter{ public Cat(){} public void me(){inc();} } The Correct answer: Nothing is output O 2 woofs and 5 mews O 2 woofs and 3 mews O 5 woofs and 5 mews O#include int main() { int a[5]; for (int i = = a[i] 1; for (int j = 0; j = a) { } = int n *pa; while (n >= 1) { n = n / 2; printf("%d *pa); pa-- ; 2 1; } Q. What is the output?class overload { int x; double y; void add(int a , int b) { x = a + b; } void add(double c , double d) { y = c + d; } overload() { this.x 0; %3D this.y = 0; } %3D } class Overload_methods { public static void main(String args[]) { overload obj int a = 2; double b - 3.2; obj.add(a, a); obj.add(b, b); System.out.println(obj.x + } = new overload(); + obj.y); } #3Run the code
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