Prove the following statement. For every real number x, if x − [x] ≥ 1/1/12 then [2x] = 2[x] + 1. Proof: Suppose x is any real number such that X- <- [x] ²/1/201 2[x] ≥ 1 or, equivalently, -Select--- Multiply both sides of the inequality by 2 to obtain 2x Now by definition of floor, x < [x] + 1, and hence ---Select--- (**). Put inequalities (*) and (**) together to obtain 2[x] + 1 ? 2x ? ✓ ---Select--- Thus, by definition of floor, [2x] = 2[x] + 1.
Prove the following statement. For every real number x, if x − [x] ≥ 1/1/12 then [2x] = 2[x] + 1. Proof: Suppose x is any real number such that X- <- [x] ²/1/201 2[x] ≥ 1 or, equivalently, -Select--- Multiply both sides of the inequality by 2 to obtain 2x Now by definition of floor, x < [x] + 1, and hence ---Select--- (**). Put inequalities (*) and (**) together to obtain 2[x] + 1 ? 2x ? ✓ ---Select--- Thus, by definition of floor, [2x] = 2[x] + 1.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.6: Inequalities
Problem 80E
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