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- JAVA LANGUAGE CODE Postfix Calculator by CodeChum Admin One good implementation of computing infix expressions is to transform them to postfix and then evaluate via the postfix expression. Infix expressions is the common way of writing arithmetic expressions. The binary operator come between them as shown below: 2 * 5 + 9 - 10 / 20 In postfix expressions, the operands come first before the operator: 2 5 * 9 + 10 20 / - A stack can be used to evaluate postfix expressions. The operands are pushed onto the Stack and when an operator is found two operands are popped and the operation is performed and finally the result is pushed back onto the Stack. The final answer will be the lone element of the Stack. Input The first line contains a positive integer n representing the number of postfix expressions. What follows are n postfix expressions themselves. 5 10 20 + 30 15 2 * + 100 20 30 + / 90 20 10 + + 0 / 9 3 - 10 + 2 * Output A single line containing the result of…Create a program in C language that calculates the month's day from a given year and year's day. Use pointers for the month and month's day variables. Don't forget to add proper errors handling in your program. Example or errors - Invalid Input- Invalid year- Invalid year day Example of input # ./month_day <year> <yearday> # Example for Feb 2nd, 2019:\$ ./month-day 2019 33Feb 02, 2019 I have this class - month-day.c - #include <stdio.h> /* month_day function's prototype*/void month_day(int year, int yearday, int *pmonth, int *pday); int main() {return 0;} Note: I don't need the calendar, please read the instructions well!!Exponent y Catherine Arellano mplement a recursive function that returns he exponent given the base and the result. for example, if the base is 2 and the result is 3, then the output should be 3 because the exponent needed for 2 to become 8 is 3 (i.e. 23 = 8) nstructions: 1. In the code editor, you are provided with a main() function that asks the user for two integer inputs: 1. The first integer is the base 2. The second integer is the result 2. Furthermore, you are provided with the getExponent() function. The details of this function are the following: 1. Return type - int 2. Name - getExponent 3. Parameters 1. int - base 2. int - result 4. Description - this recursive function returns the exponent 5. Your task is to add the base case and the general case so it will work Score: 0/5 Overview 1080 main.c exponent.h 1 #include 2 #include "exponent.h" 3 int main(void) { 4 int base, result; 5 6 printf("Enter the base: "); scanf("%d", &base); 7 8 9 printf("Enter the result: ");…
- CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;C++ performing addition on complex data using class and object. should ask for real and imaginary part of two complex numbers, and display the real and imaginary parts of their sum output should be Complex number 1: 1+7i Complex number 2: 3+6i Sum of complex number: 4+13i#include using namespace std; bool isPalindrome(int x) { int n=0,val; val = x; while(x > 0) { n = n * 10 + x % 10; x = x / 10; } } int main() { int n; cin >>n; if(isPalindrome(n)) { cout <
- on c++ Question 01: Write a recursive function that converts a decimal number into a binary number as a string. The function header is: string decimalToBinary(int value) Write a test program that prompts the user to enter a decimal number and displays its binary equivalent. Question 02: Write a recursive function that parses a binary number as a string into a decimal integer. The function header is: int binaryToDecimal(const string& binaryString) Write a test program that prompts the user to enter a binary string and displays its decimal equivalent.Python Test Program: import recursive_functionsimport mathdef main():# Test factorialprint('Testing factorial.')assert recursive_functions.factorial(0) == 1assert recursive_functions.factorial(1) == math.factorial(1)== 1assert recursive_functions.factorial(2) == math.factorial(2)== 2assert recursive_functions.factorial(5) == math.factorial(5)== 120assert recursive_functions.factorial(7) == math.factorial(7)== 5040print('All tests pass for `factorial` ()\n')# Test sum_recursivelyprint('Testing sum_recursively.')assert recursive_functions.sum_recursively(0) == 0assert recursive_functions.sum_recursively(1) ==sum(range(1+1)) == 1assert recursive_functions.sum_recursively(2) ==sum(range(2+1)) == 3assert recursive_functions.sum_recursively(10) ==sum(range(10+1)) == 55print('All tests pass for `sum_recursively` () ')# Test sumlist_recursively(l)print('Testing sumlist_recursively.')assert recursive_functions.sumlist_recursively([1,2,3])…on c++ these to q are related to each Question 01: Write a recursive function that converts a decimal number into a binary number as a string. The function header is: string decimalToBinary(int value) Write a test program that prompts the user to enter a decimal number and displays its binary equivalent. Question 02: Write a recursive function that parses a binary number as a string into a decimal integer. The function header is: int binaryToDecimal(const string& binaryString) Write a test program that prompts the user to enter a binary string and displays its decimal equivalent.
- ✓ Allowed languages C Problem Statement Write a C Program that will compute for npr (n taken r permutations). Input Input starts with a number N and is followed by N pairs of numbers n and r. Output Output n Pr Limits 1Stack using C++ programmijng language please Write a program to input an arithmetic expression, then 1. Match nested brackets found the expression, if they are matched correctly proceed to step 2.2. Evaluate the expression. Please not that the operands of the expression may contain more than one digit. the cin of the arithmetic expression is :: ((5+(6/2*3)-2)+1)= you can use this function also ::: struct node { int data; node *next; node(int d,node *n=0) { data=d; next=n; } }; class stack { node *topp; public: stack(); void push(int el); bool pop(); int top(); bool top(int &el); //~stack(); //void operator=(stack &o); //stack(stack &o); }; stack::stack() { topp=0; } void stack::push(int el) { topp=new node(el,topp); } bool stack::pop() { if(topp==0) return false; node *t=topp; topp=topp->next; delete t; return true; } int stack::top() { if(topp!=0) return topp->data; } bool stack::top(int &el) { if(topp==0) return false; el=topp->data; return true; }Matrix Problem Code this in C Write a program that reads two matrices of integers. It then generates the sum, difference, and product of the two matrices. The sum of the two matrices of the same size is a matrix with elements that are the sums of the corresponding elements of the two given matrices. Addition is not defined for matrices of different sizes. If A and B are matrices of the same size, then we define subtraction as follows: A – B = A + (-B). Thus, to subtract matrix B from matrix A, we simply subtract corresponding elements. To multiply a matrix by another matrix we need to do the "dot product" of rows and columns. The "Dot Product" is where we multiply matching members, then sum up: (1, 2, 3) • (7, 9, 11) = 1×7 + 2×9 + 3×11 = 58 We match the 1st members (1 and 7), multiply them, likewise for the 2nd members (2 and 9) and the 3rd members (3 and 11), and finally sum them up. Use the following definitions:#define ROW 6#define COL 6void add(int matrixResult[][COL],int…SEE MORE QUESTIONS
