Problem: Tests reveal that a normal driver takes about 0.75 s before he or she can react to a situation to avoid a collision. It takes about 3 s for a driver having 0.1%% alcohol in his system to do the same Questions 1: if such drivers are traveling on a straight road at 30 mph (44 ft/s) and their cars can decelerate at 23 ft/s^2, determine the shortest stopping distance d for normal driver from the moment he or she see the pedestrians. Express your answer with the appropriate units. Question 2: Determine the shortest stopping distance d for drunk driver from the moment he or she see the pedestrians. Express your answer with the appropriate units.
Problem: Tests reveal that a normal driver takes about 0.75 s before he or she can react to a situation to avoid a collision. It takes about 3 s for a driver having 0.1%% alcohol in his system to do the same Questions 1: if such drivers are traveling on a straight road at 30 mph (44 ft/s) and their cars can decelerate at 23 ft/s^2, determine the shortest stopping distance d for normal driver from the moment he or she see the pedestrians. Express your answer with the appropriate units. Question 2: Determine the shortest stopping distance d for drunk driver from the moment he or she see the pedestrians. Express your answer with the appropriate units.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Problem: Tests reveal that a normal driver takes about 0.75 s before he or she can react to a situation to avoid a collision. It takes about 3 s for a driver having 0.1%% alcohol in his system to do the same
Questions 1: if such drivers are traveling on a straight road at 30 mph (44 ft/s) and their cars can decelerate at 23 ft/s^2, determine the shortest stopping distance d for normal driver from the moment he or she see the pedestrians.
Express your answer with the appropriate units.
Question 2: Determine the shortest stopping distance d for drunk driver from the moment he or she see the pedestrians.
Express your answer with the appropriate units.
Please help me with both of these questions, make sure to show neat hand writing and explaintions. Thnak you
Transcribed Image Text:v, = 44 ft/s
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