Problem 81 Write a query to display the highest book cost in the system (Figure P7.81). Most Expensive 12995 Figure 7.81
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- A unique identifier for a data row that consists of more than one field is commonly called a: primary plus key composite primary key foreign key none of the aboveDatabase Schema The schema for the Ch07_FACT database is shown below and should be used to answer the next several problems. Click this image to view it in its own tab. FIGURE P7.56 THE CH07_FACT ERD CHECKOUT PATRON PK Check Num PK Pat ID FK1 Book_Num FK2 Pat_ID Check_Out_Date Check_Due_Date Check_In_Date >0-----H- Pat_FName Pat LName Pat_Type BOOK AUTHOR PK Book_Num PK Au ID Book_Title Book_Year Book_Cost Book_Subject FK1 Pat_ID Au_FName Au_LName Au_BirthYear WRITES PK,FK1 Book Num PK,FK2 Au ID The CIS Department at Tiny College maintains the Free Access to Current Technology (FACT) library of e-books. FACT is a collection of current technology e-books for use by faculty and students. Agreements with the publishers allow patrons to electronically check out a book,assume that a database has a table named Stock, with thefollowing columns:Column Name TypeTrading_Symbol nchar(10)Company_Name nchar(25)Num_Shares intPurchase_Price moneySelling_Price money Write a Select statement that returns the Trading_Symbol column only from the rows where Selling_Price is greater than Purchase_Price and Num_Shares is greater than 100.
- Write Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule with the lesson date/time, horse ID, and the student's first and last names. Order the results in ascending order by lesson date/time, then by horse ID. Unassigned lesson times (student ID is NULL) should not appear in the schedule. Hint: Perform a join on the Student and LessonSchedule tables, matching the student IDs.Write Mysql code for: The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.assume that a database has a table named Stock, with thefollowing columns:Column Name TypeTrading_Symbol nchar(10)Company_Name nchar(25)Num_Shares intPurchase_Price moneySelling_Price money Write a Select statement that returns only the Trading_Symbol column from every row in the table.
- Use Mysql code The database has three tables for tracking horse-riding lessons: Horse with columns: ID - primary key RegisteredName Breed Height BirthDate Student with columns: ID - primary key FirstName LastName Street City State Zip Phone EmailAddress LessonSchedule with columns: HorseID - partial primary key, foreign key references Horse(ID) StudentID - foreign key references Student(ID) LessonDateTime - partial primary key Write a SELECT statement to create a lesson schedule for Feb 1, 2020 with the lesson date/time, student's first and last names, and the horse's registered name. Order the results in ascending order by lesson date/time, then by the horse's registered name. Make sure unassigned lesson times (student ID is NULL) appear in the results. Hint: Perform a join on the LessonSchedule, Student, and Horse tables, matching the student IDs and horse IDs.Access Assignment Problem: JMS TechWizards is a local company that provides technical services to several small businesses in the area. The company currently keeps its technicians and clients’ records on papers. The manager requests you to create a database to store the technician and clients’ information. The following table contains the clients’ information. Client Number Client Name Street City State Postal Code Telephone Number Billed Paid Technician Number AM53 Ashton-Mills 216 Rivard Anderson TX 78077 512-555-4070 $315.50 $255.00 22 AR76 The Artshop 722 Fisher Liberty Corner TX 78080 254-555-0200 $535.00 $565.00 23 BE29 Bert's Supply 5752 Maumee Liberty Corner TX 78080 254-555-2024 $229.50 $0.00 23 DE76 D & E Grocery 464 Linnell Anderson TX 78077 512-555-6050 $485.70…assume that a database has a table named Stock, with thefollowing columns:Column Name TypeTrading_Symbol nchar(10)Company_Name nchar(25)Num_Shares intPurchase_Price moneySelling_Price money Write a Select statement that returns all the columns from the rows where Trading_Symbol starts with "SU".
- Assume that the Authors table is already built in the database with the following specifications: Authors: Column Name Data Type constrains Authors ID Author Name Varchar2(10) |Varchar2(30) Primary key Unique You Need to Create the Books table with the following specifications Column Name Data Type Constrains ISBN Book Title Book Price Author id Number (10) Varchar2(40) Number (4,2) Varchar2(10) Primary key Not Null referencing the Author_ID in the Author Table Complete the create statement by drag and drop the correct word: Create Table lblank (ISBN Number (10) plank, Book Title Varchar2blank ) Not Null, Book Price Number(4, 2), Auther IR blank (10) references Jolank (blank ); Author ID Books Number||Authors Not Nul Varchar2| Primary Key 40 h (United States)Indexing Consider a relational database that consists of the relational tables created by the following CREATE TABLE statements: CREATE TABLE PART( P_PARTKEY NUMBER(12) NOT NULL, P_NAME VARCHAR(55) NOT NULL, P_RETAILPRICE NUMBER(12,2) NOT NULL, CONSTRAINT PART_PEKEY PRIMARY KEY (P_PARTKEY) ); CREATE TABLE SUPPLIER( S_SUPPKEY NUMBER(12) NOT NULL, S_NAME CHAR(25) NOT NULL S_NATIONKEY NUMBER(12) NOT NULL, S_PHONE CHAR(15) NOT NULL, CONSTRAINT SUPPLIER_PKEY PRIMARY KEY (S_SUPPKEY) ); CREATE TABLE PARTSUPP( PS_PARTKEY NUMBER(12) NOT NULL, PS_SUPPKEY NUMBER(12) NOT NULL, PS_SUPPLYCOST NUMBER(12,2) NOT NULL, CONSTRAINT PARTSUPP_PKEY PRIMARY KEY (PS_PARTKEY, PS_SUPPKEY), CONSTRAINT PARTSUPP_FKEY1 FOREIGN KEY (PS_PARTKEY) REFERENCES PART(P_PARTKEY), CONSTRAINT PARTSUPP_FKEY2 FOREIGN KEY (PS_SUPPKEY) REFERENCES SUPPLIER(S_SUPPKEY) ); Determine what index should be created to improve the performance of the queries listed below in the best possible way. Consider each one of the…Assume that a database has a table named Stock, with the following columns:Column Name TypeTrading_Symbol nchar(10)Company_Name nchar(25)Num_Shares intPurchase_Price moneySelling_Price moneyWrite a Select statement that returns the Trading_Symbol column only from the rows where Purchase_Price is greater than $25.00.