Problem 3. Parameter Passing Consider the following block. Assume dynamic scoping. 1 ( int y; 2 int z; 3 4 e 5 6 7 8 e 9 10 11 12 13 14 15 }; y := 6; { int }; f(int a) { y = a +1; return (y+a) }; int g(int x) { y = f(x+1)+2; z = f(x-y+2); return (z+1) } z = g(y*2); a) Draw the runtime stack after each line executes given that both parameters a and x are passed using Call-by-Name. What are the values of y and z after line 13 executes? b) Draw the runtime stack after each line executes given that both parameters a and x are passed using Call-by-Need. What are the values of y and z after line 13 executes?
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- C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".main.cpp 1 @include 2 using namespace std; int maxResult() 4-( int maxVal = 0; 6. for (int i = 0; i <= n; i += a) { for (int j = e; j <= n i;j += b) !! 10 (float)(n - (i + j)) / (float)(c); 11 float z = 12 if (floor (z) { int x = i / a; int y 13 ceil(z)) 14 15 16 j/ b; max (maxVal, x + y + (int)z); 17 maxVal = 18 19 20 21 22 return maxVal; 23 } 24 int main() 26 { 25 27 28 cout << maxResult( ); 29 30 return 0; 31 } Input Compilation failed due to following erors) main.cpp:7:23: error: 'n was not declared in this scope 7 for (int i = 0; i <= n; i t a) main.cpp:7:31: error: 'a' was not declared in this scope 7 for (int i 0; i <= n; i t a) main.cpp:9:36: error: 'b' was not declared in this scope for (int j = 0; j <- n i; j b) %3D main.cpp:11:45: error: was not declared in this scopeCFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;In C++ QUESTION 14 class rectangleType { public: void setLengthWidth(double x, double y); //Sets the length = x; width = y; void print() const; //Output length and width double area(); //Calculate and return the area of the rectangle (length*width) double perimeter(); //Calculate and return the perimeter (length of outside boundary of the rectangle) private: double length; double width; }; Write the function definition for the function perimeterclass A Q5: Correct the following code fragment and what will be the final results of the variable a and b { protected int x1,y1,z; public: A(a, b,c):x1(a+2),y1(b-1),z(c+2) { for(i=0; i<5;i++) x1++; y1++;z++;}}; class B { protected: int x,y; public: B(a,b):x(a+1),y(b+2) { for(i=0; i<5;i++) x+=2; y+=1;}}; class D:public B, virtual public A { private: int a,b; public: D(k,m,n): a(k+n), B(k,m),b(n+2),A(k,m,n) { a=a+1;b=b+1;}}; int main() {D ob(4,2,5);}int f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?Q1 function myFunc() { let a = 10; if (true) { Q3 } } let a = 5; console.log(a); Q4 console.log(a); Q2 const square = num => num * num; console.log(square(3) + 5); myFunc(); let x = 30; let y "200"; console.log(x+y); const nums = [10, 20, 8, 17]; nums.filter(e=> e > 10); console.log(nums); Q5 const nums = [30, 35, 42, 20, 15]; console.log(nums.every (num => num > 20)); January 15C++ Dynamic Programs Hoskins College offers both curriculum and continuing education courses. Write a program that dynamically tracks these courses using an array of object pointers. Every course (both curriculum and continuing education) has a course id, title, room number, and number of contact hours. A curriculum course has credit hours and tuition rate. Tuition is calculated by multiplying the course's credit hours by tuition rate. A continuing education course has a flat fee (cost). Implement a show() function in every class that displays the data in the object. Part A: Create an inheritance-based collection of classes to represent these different courses. Include code in main to test your work by instantiating objects of the two derived classes. Part B: Modify your program. Remove the objects you created in main to test the classes. Modify the base class so that show() becomes a virtual class. In main, create a single array capable of holding pointers to objects of both…#include using namespace std; (а) class Fraction{ int x, y; public: Fraction (int a, int b) {x=a; y=b;}; int getx(){return x;} int gety() {return y;} } ; int main() Fraction n(3, 7); ++n; cout << "x/y: " <« n.getx()<< "/" « n.gety()<void fact(int num) { int k,f=1; for (k=1;k<=num; k++) f=f*k; cout<< f; int main() { int arri[3]={3,2,1} ; for(int i=0;i<3;i++) fact(arri[i]); } 261 O 621 O 7 4621- b) 7 8 2 6 d) 8 7 6 2 int arr[4]- {2, 6, 7, 8}; for (int i- 3; i>=0; i--) cout<SEE MORE QUESTIONSRecommended textbooks for youEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENTEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT