Problem 3. In a certain region of space, the electric field is constant in direction (say horizontal, in the x direction), but its magnitude decreases from 560 N/C at x = 0 to 410 N/C at x= 25 m. Consider the gaussian surface in the form a cubical box of side 25 m where the box is oriented so that four of its sides are parallel to the field lines. (see figure below). (&o=8.85x10-12 C²/N·m², k = 9 x10° N.m²/C²). (a) Find the flux through the vertical surface on the left at x= 0. (b) Calculate the flux through the vertical surface on the right at x= 25 m. (c) Determine the average charge density within the cubical box. x=0 Ē x = 25 m 1-25 m- E

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter25: Gauss’s Law
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Problem 3. In a certain region of space, the electric field is constant in direction (say horizontal, in the x
direction), but its magnitude decreases from 560 N/C at x 0 to 410 N/C at x= 25 m. Consider the
gaussian surface in the form a cubical box of side 25 m where the box is oriented so that four of its sides
are parallel to the field lines. (see figure below). ( = 8.85x10-¹2 C²/N·m², k = 9 x10° N·m²/C²).
(a) Find the flux through the vertical surface on the left at x= 0.
(b) Calculate the flux through the vertical surface on the right at x= 25 m.
(c) Determine the average charge density within the cubical box.
x=0
x = 25 m
+25 m-
Ë
Transcribed Image Text:= Problem 3. In a certain region of space, the electric field is constant in direction (say horizontal, in the x direction), but its magnitude decreases from 560 N/C at x 0 to 410 N/C at x= 25 m. Consider the gaussian surface in the form a cubical box of side 25 m where the box is oriented so that four of its sides are parallel to the field lines. (see figure below). ( = 8.85x10-¹2 C²/N·m², k = 9 x10° N·m²/C²). (a) Find the flux through the vertical surface on the left at x= 0. (b) Calculate the flux through the vertical surface on the right at x= 25 m. (c) Determine the average charge density within the cubical box. x=0 x = 25 m +25 m- Ë
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