Problem 255. Two points lying on the same lield line are separated by a distance XY = 1 = 10 cm in vacuum, in a uniform magnetic field where the magnitude of the magnetic induction vector is B = = 0.02 tesla. An electron accelerated by a potential difference of 800 volts passes through the point X. Its velocity encloses an angle a with the field lines. What should be the measure of the angle a so that the electron also passes through the point Y? The charge of an electron is 1.6 10 19 coulombs, and its mass is 9. 10-3l kg. %3D Y B
Problem 255. Two points lying on the same lield line are separated by a distance XY = 1 = 10 cm in vacuum, in a uniform magnetic field where the magnitude of the magnetic induction vector is B = = 0.02 tesla. An electron accelerated by a potential difference of 800 volts passes through the point X. Its velocity encloses an angle a with the field lines. What should be the measure of the angle a so that the electron also passes through the point Y? The charge of an electron is 1.6 10 19 coulombs, and its mass is 9. 10-3l kg. %3D Y B
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Transcribed Image Text:Problem 255. Two points lying on the same lield
line are separated by a distance XY = L = 10 cm
in vacuum, in a uniform magnetic field where the
magnitude of the magnetic induction vector is B =
= 0.02 tesla. An electron accelerated by a potential
difference of 800 volts passes through the point X.
Its velocity encloses an angle a with the field lines.
What should be the measure of the angle oa so that the
electron also passes through the point Y? The charge
of an electron is 1.6 10 19 coulombs, and its mass is 9- 10-31 kg.
%3!
Y
B
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