PROBLEM 2.15 17. The position of a particle moving along the x-axis is given by x = (11 + 14t – 2.0t2), where t is in seconds and x is in meters. What is the average velocity during the time interval from t = 1.0 s tot= 4.0 s? 6 m/s b. с. 8 m/s d. 2 m/s a. 4 m/s
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- Example 2:A particle moving along a straight line is subjected to a deceleration a = (-2v') m/s², where v is in m/s. If it has a velocity v = 8 m/s and a position s = 10 m when 0, determine its velocity and position when t = 4 s. t = %3D1. 1) The acceleration of a particle moving along a straight line is a = (-C· /v) m/s², where C is a constant and vis velocity in m/s. If the constant Cis 1.5, and the initial velocity vo = 6.9 m/s at time t= 0, determine how far (in m) it has traveled when it stops. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point.Consider the portion of an excavator shown. At the instant under consideration, the hydraulic cylinder is extending at a rate of 6 in./sec, which is decreasing at the rate of 3 in./secevery second. Simultaneously, the cylinder is rotating about a horizontal axis through O at a constant rate of 12 deg/sec. Determine the velocity v and acceleration a of the clevis attachment at B. 2.7 B 3.6' PA 37° Part 1 Correct Determine the indicated terms used in the velocity and acceleration formulas. 2.7 B 3.6' 37° Answers: r- 75.6 in. 37 トー 6 in./sec 9 - 0.21 rad/s Fー -3 in./sec? 0 - rad/s?
- What is the local acceleration (m/s) for a fluid particle that travels along a path and the 3 0.7 with velocity given by s t radius of curvature is 3.4m, where s is in meters and t is in seconds? s=2.5m, t=0.5 s. Select one: a. a = 111.0 m/s2 b. a = 49.3 m/s2 c. a =27.2 m/s • d. a = 13.5 m/s2 O e. a = 73.8 m/s2Q1. A driver enters a curved car at 72 km/h, slows down, causing the speed to drop at a steady rate of 4.5 km/h every second. If the radius of curvature is 16.7 m. Find the acceleration of the car after 4 seconds from the driver starting to slow down.1. The position of a particle moving along the x-axis is described by x = t – 108t in where t is the time in sec. For the time interval t= 0 to t = 10 s, (a) plot the position, velocity, and acceleration as a function of time (b) find the displacement of the particle and (c) determine the distance traveled by the particle.
- The position of a particle is given by s= 0.39³ -0.69t2-2.04t+4.42, where s is in feet and the time t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 6 seconds of motion. After you have the plots, answer the questions as a check on your work. Questions: 0 Whent 0.8 sec, v= When t 5.2 sec, v= 2 3 -+s, ft ft/sec. a ft/sec, a The positive time at which the particle changes direction is i sec. ft/sec2 ft/sec²EX- function of time t (in second ) is : The position s ( in meters ) of a moving body as s - 2t + 5t – 3 ; find : a a) The interval from t= 0 to t= 2 seconds . b) The body’s velocity at t=2 seconds . displacement and average velocity for the timeTOPIC: Equation of Motion (NORMAL AND TANGENTIAL) Fn= Man Ft= Mat Given a 1400 kg car that travels along a road with increasing vertical profile y = 0.0003x². If the constant velocity of the car is 30 m/s. of the distance is at 210m, Determine the x-component of the velocity (m/s) of the car. Compute the total force (KN). PLEASE ANSWER WITH A COMPLETE AND DETAILED SOLUTIONS. THANK YOU
- The displacement of a particle is given by s = 4t3 - 54t2 + 105t - 49 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 10 seconds of motion. After you have made the plots, answer the questions. Questions: Att- 2 sec, ft. v= ft/sec, a = ft/sec? %3D Att = 4.1 i ft. v= i ft/sec, a = i ft/sec? sec, Att = 8.7 i ft, v= i ft/sec, a = i ft/sec? sec, The velocity is zero when t = i sec and whent%3D i secIf a ball is thrown into the air with a velocity of 52 ft/s, its height in feet t seconds later is given by y = 52t – 16t2. (a) Find the average velocity for the time period beginning when t = 2 and lasting for each of the following. (i) 0.5 seconds 70 X ft/s (ii) 0.1 seconds 69.5 X ft/s (iii) 0.05 seconds 68.5 ft/s (iv) 0.01 seconds 70 X ft/s (b) Estimate the instantaneous velocity when t = 2. 70 X ft/sThe displacement of a particle is given by s=3t3-57t² + 114t 44 where s is in feet and it is in seconds. Plot the displacement, velocity. and acceleration as functions of time for the first 18 seconds of motion. After you have made the plots, answer the questions. Questions: Att 4.5 sec. Att 9 sec, Att 14.3 sec, A34 The velocity is zero when t 1 ft.v= ft. v ft, v= === sec and when t= !!! ft/sec, a= ft/sec. a ft/sec. a ft/sec ft/sec ft/sec