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- 1、Counting Primitive Operations void STRAITMAXMIN(A,n,max,min) //Set the maximum value in A to max and the minimum value to min { int i,n max=min=A[1] for i=2 to n { if A[i]> max max=A[i]; if A[i]< min min=A[i]; } }CPU Priority Scheduling-preemptive: Write a Java program to implement a priority scheduling algorithm that uses low number to represent high priority. Your program should first prompts the user to input a list of process ID, arrival time, burst time, and priority for each process to be run on the CPU. The list is terminated by 0 0 0 0 for the process ID, arrival time, burst time, and priority. The program output should draw a Gantt chart (as text) that shows the scheduling order of the processes using the Priority scheduling algorithm. Also print the turnaround time, response time, and waiting time for each process along with their average for all processes. Make sure to display very helpful messages to the user for input and output.3- Evaluate the following statement using stack : T= calculate (3) ; Where calculate () defined as follows : int calculate ( int n) { int x , y; if ( n<=1) return 1; else { x = calculate (n – 1) ; y = calculate ( n - 2 ); return x * y; } }
- A sequence of instructions may be used to see the function's return address. Any modifications to the stack must be made with the return of the method to its caller in mind.Question 37 public static void main(String[] args) { Dog[] dogs = { new Dog(), new Dog()}; for(int i = 0; i >>"+decision()); } class Counter { private static int count; public static void inc() { count++;} public static int getCount() {return count;} } class Dog extends Counter{ public Dog(){} public void wo(){inc();} } class Cat extends Counter{ public Cat(){} public void me(){inc();} } The Correct answer: Nothing is output O 2 woofs and 5 mews O 2 woofs and 3 mews O 5 woofs and 5 mews O// Assume all libraries are included void QQ(int n); // int main () { // Random questions QQ (5) ; 3 4 6. 7 8. 9. 10 return 0; 11 } // void QQ(int n) 12 13 14 { if(n >= 1) { 15 16 17 cout << n; QQ (--n); } else 18 19 20 21 cout << n; 22 } // 23
- C++ ProgrammingActivity: Linked List Stack and BracketsExplain the flow of the main code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS int main(int argc, char** argv) { SLLStack* stack = new SLLStack(); int test; int length; string str; char top; bool flag = true; cin >> test; switch (test) { case 0: getline(cin, str); length = str.length(); for(int i = 0; i < length; i++){ if(str[i] == '{' || str[i] == '(' || str[i] == '['){ stack->push(str[i]); } else if (str[i] == '}' || str[i] == ')' || str[i] == ']'){ if(!stack->isEmpty()){ top = stack->top(); if(top == '{' && str[i] == '}' || top == '(' && str[i] == ')' ||…Language: c++ Please solve problem completely according to requirement, program should must be follow all the rules of menu base system which are required and write in question: Attach the output's screentshots and explain every line with comments: Whole code should be user defined inputs not fix: Task : Address Book (List)• Your program will be a menu driven program. Address book will be implemented using the ArrayList.Description: We want to build an address book that is capable of storing name, address & phone number of a person. Address book provides functionality in the form of a menu. The feature list includes:• Add – to add a new person record• Delete – to delete an existing person record by name• Search – to search a person record by name Sort - to sort the file after adding a new person record. · Exit – to exit from applicationC++ ProgrammingActivity: Deque Linked List Explain the flow of the main code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS int main(int argc, char** argv) { DLLDeque* deque = new DLLDeque(); int test; cin >> test; //Declarations int tempnum; int num; int sum; int count; bool addfirst = false; bool addlast = false; bool remfirst = false; bool remlast = false; switch (test) { case 0: //Implementation do{ cin >> num; if(num == 0){ break; } //Reset tempnum = num; count = 0; sum = 0; addfirst = false; addlast = false; remfirst = false; remlast =…Weighted Job Scheduling in C language only please Problem statement: You are given a list of jobs where each job has a start time, finish time, and the profit associated with that job, find the maximum profit subset of non-overlapping jobs. Problem description: The problem wants you to find the maximum profit that you can make after performing a certain number of jobs such that each job has a certain condition that you can start a job only if the start time of the current job is greater than the finish time of the previous job. You are required to develop some algorithm such that the job start time and the finish time does not coincide with other jobs. Output: (Attached photo)SEE MORE QUESTIONS