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Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) near0 such that g(t) = P3(t) + R3(0, 1) in some interval where R3(0, 1) is the remainder term. Writing P3(t) as P3(1)=ao+at+a21² + a31³, calculate the coefficient a3. - cos(57) sin(31)

Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) near0 such that g(t) = P3(t) + R3(0, 1) in some interval where R3(0, 1) is the remainder term. Writing P3(t) as P3(1)=ao+at+a21² + a31³, calculate the coefficient a3. - cos(57) sin(31)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 3E
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Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) cos(57) sin(37) near0 such that g(t) = P3(t) + R3(0, 1) in some interval where R3(0, 1) is the remainder term. Writing P3(t) as P3(1)=ao+at+a27² + a31³, calculate the coefficient a3.
Transcribed Image Text:Problem #1: By Taylor's theorem, we can find a Taylor polynomial P3(1) of degree 3 for the function g(t) cos(57) sin(37) near0 such that g(t) = P3(t) + R3(0, 1) in some interval where R3(0, 1) is the remainder term. Writing P3(t) as P3(1)=ao+at+a27² + a31³, calculate the coefficient a3.
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