Problem 1: = 0.1 m. In the figure below four wires are on the corners of a square with a side of length L Each of the wires has a current I = 2 A. The wire on the bottom-left edge of the square has a current into the page. The remaining three wires on the square have a current out of the page. What is B at point P, the center of the square? Answer: B = Ho Ho¹ĵ = (8 × 10−6 T)î – (8 × 10− T)ĵ. πL πι I L √2 2 I L √2 L ·L/ 2 الله انکار L 12 I L 22 2 I L

University Physics Volume 2
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Chapter12: Sources Of Magnetic Fields
Section: Chapter Questions
Problem 85AP: , A ray long, thick, cylindrical wire of radius R carries a current density J that varies across its...
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Problem 1:
=
0.1 m.
In the figure below four wires are on the corners of a square with a side of length L
Each of the wires has a current I = 2 A. The wire on the bottom-left edge of the square has a
current into the page. The remaining three wires on the square have a current out of the page.
What is B at point P, the center of the square?
Answer: B = Ho Ho¹ĵ = (8 × 10−6 T)î – (8 × 10− T)ĵ.
πL
πι
I
L
√2
2
I
L
√2
L
·L/
2
الله انکار
L
12
I
L
22
2
I
L
Transcribed Image Text:Problem 1: = 0.1 m. In the figure below four wires are on the corners of a square with a side of length L Each of the wires has a current I = 2 A. The wire on the bottom-left edge of the square has a current into the page. The remaining three wires on the square have a current out of the page. What is B at point P, the center of the square? Answer: B = Ho Ho¹ĵ = (8 × 10−6 T)î – (8 × 10− T)ĵ. πL πι I L √2 2 I L √2 L ·L/ 2 الله انکار L 12 I L 22 2 I L
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