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- pH= 2.) Calculate the pH in a 0.584 M solution of pentanoic acid. Pentanoic acid is CH3CH2CH2CH2CO2H and it's Ka = 1.44 x 10-5.Iron(III) Chloride Test Saved BIIIU X2 | X² | → Ix Normal Alcohol FeCl3 test color Ethanol 2-Propanol 2-Methyl-2-propanol Cyclohexanol Phenol N/A Unknown ll !!Lab and Mastering arch 2 S T X ecollege.com/course.html?courseld=17811238&OpenVellumHMAC=43d44d5cb2c3026457d713785d3... A f10 P → Pearson X I y Enter a balanced chemical eq X (12 O * * @ Sign i 76°F Mostly cloudy @ prt sc delete backspace home num lock 7 ENG end 9:08 PM 4/14/2023
- In a 0.73 mM aqueous solution of trimethylacetic acid (C₂H₂CO₂H), what is the percentage of trimethylacetic acid that is dissociated? You can find some data that is useful for solving this problem in the ALEKS Data resource. Round your answer to 2 significant digits. 1% 00 x10 X $Technology O Ask a Librarian 6 Box Facebook Twitter Question 7 The product(s) of the following reaction should be (choose all that apply): CH3O–ĈCH2(CH2)4CH3 + NaOH(aq) > 14 John Wiley & Sons, Inc. All rights reserved. O amine O carboxylic acid O alcohol O aromatic O ketone O aldehyde O carboxylate ion1) Answer the following questions using the table below: Acid Benzoic Acid, C6H5CO2H Benzylammonium ion, C6HSCH2NH3* Chloroacetic acid, CICH2CO2H Hydrogen Sulfide, H2S Ka 6.31 x 10-5 4.47 x 10-10 1.35 x 10-3 1.00 x 10-7 Nitrous Acid, HNO2 4.47 x 104 a) Which is the strongest acid? b) Which acid has the highest pH, and what is the chemical formula of the conjugate base? c) Write the reaction of nitrous acid (HNO2) acting as a Brønsted-Lowry acid in water and write the Ka expression.
- Consider propanoic (CH3CH2CH2CO2H) acid and pentanoic (CH3CH2CH2CH2CO2H) acid and the corresponding alcohols with the same number of carbons, propanol (CH3CH2CH2COH) and pentanol (CH3CH2CH2CH2COH). Select the class of compound that is more soluble. {one answer] Select the best explanation for your answer to the previous question. [a second answer] Group of answer choices a. The solubility of alcohols in water decreases with increasing chain length. b. Propanoic acid and pentanoic acid are more soluble in water than the corresponding alcohol. c. Carboxylic acids are generally more soluble in water than alcohols of the same chain length because of increased hydrogen bonding with the -COOH functional group. d. Propanol and pentanol are more soluble in water than the corresponding carboxylic acid e. The solubility of carboxylic acids in water decreases with increasing chain length. f. Alcohols are generally more soluble in water than carboxylic acids of the same…1. Which is the hydrolytic reaction for the basic compound ethylamine (CH:CH:NH:)? CH;CH,NH2 (aq) + H;01) = CH;CH2NH (ae) + OHiag) a. CH;CH;NH2(ag) b. + H201) = CH3CH2NHaq) + H30taq) CH3CH,NH2(ag) + H20(1) = CH3CH2NHag) + OH ag) + H3Otaq) c. CH3CH,NH2(ag) + H20() = CH,CH2NH. d. (aq) 2. Which represents the hydrolytic reaction corresponding to the K: or the second acid dissociation constant of H.SeO:? H2SEO3(ag) + H20) HSE05(ae) + H30tag) a. + H2O(1) = H2SEO3(aq) + OH(ag) (aq) + H201) = Se0ž (aq) b. HSEO3 (aa) + H30tag) (aq) с. Seof + H20) = HSeO5 (aq) + OH(aq) (aq) d.Refer to the following information to answer questions 1 to 9: As a biotechnologist working for a pharmaceutical company, you as tasked with preparing the cardiac antiarrhythmic agent Amelfolide from p-nitrobenzyl chloride and 2,6-dimethyl aniline (Figure 2.1). You are provided the starting materials and asked to prepare 7.50g of pure material. No other instructions are given to you. MW 2,6-dimethylaniline = 121.18 g/mol MW p-nitrobenzyl chloride = 185.56 g/mol MW Amelfoliode = 270.29 g/mol %3D NH2 CI O2N O2N When developing a synthetic scheme, the first thing to do is check the scientific literature to see if someone has done this reaction before you. Upon performing a literature search, you identify a publication where a group from Japan has performed the same reaction you are tasked with completing. The paper is in Japanese and you cannot read the details of the procedure, however, you can make out that the reaction is performed using DCM as the solvent and proceeds with a yield of…
- Professor Rowan is preparing for his experiment in Sinnoh Lab. The structures of the substances that he will use are presented below: Substance Turtwig Substance Piplup Substance Chimchar H 'o H H. H. H' H. H Molar Mass: 106.12g/mol Molar mass: 122.12g/mol Molar mass: 92.14g/mol A. What is/are the IMFA present in each of the substances? (LDF - London Dispersion Forces, DDF- Dipole-dipole Forces, HB- Hydrogen Bonding) B. Determine the most possible melting point of each of the substances. (Possible melting points: 122 °C, -26 °C, -95 °C) C. Rowan's Apprentice, Dawn, needs a solid starting material in her experiment at room temperature (at 25°C). Among the three substances, what is Dawn's starting material?Balance the following redox reactions, to their simplest form, by supplying the correct coefficients before each compound for #s 1-15. The unknown coefficients of the compounds should be whole numbers. Note: The reactions below are not yet balanced.1) Hydrolysis of Methyl Salicylate: Methyl Salicylate (C8H8O3) + sodium Hydroxide (NaOH) -> sodium Salicylate ( NaC7H5O3) + Methanol (CH3OH) 2) Acidification of Sodium Salicylate: Sodium salicylate (NaC7H5O3) + HCL -> Salicylic acid (C7H603) + sodium chloride (NaCL) Could you find the theoretical yield for me? 2.15g of methyl salicylate was used. 25ml of sodium hydroxide (2m solution) was used for hydrolysis and 2ml of hydrochloric acid was used for the acidification. This produced a yield of 1.53g of salicylic acid.