Po undergoes four decay reactions: a, B, a, ß. Step 1. °Po undergoes a decay to give Pb 84 Step 2. Pb undergoes B decay to give Bi In the third step, Bi-214 undergoes a decay. What is the product of this step? symbol - mass number - atomic number =

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter18: Nuclear Chemistry
Section18.4: Rates Of Disintegration Reactions
Problem 18.6E
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The first four steps in the radioactive decay sequence of Po-218 are a, B, a, B.
To write the reaction equations for this decay series, first determine the product of the first step.
a decay of Po-218 gives:
symbol = Pb
mass number = 214
atomic number
82
Po undergoes four decay reactions: a, B, a, B.
Step 1.
*Po undergoes a decay to give Pb
In the second step, Pb-214 undergoes B decay. What is the product of this step?
84
symbol = Bi
mass number = 214
atomic number = 83
Po undergoes four decay reactions: a, B, a, B.
Step 1.
218 Po undergoes a decay to give Pb
Step 2.
Pb undergoes B decay to give Bi
82
In the third step, Bi-214 undergoes a decay. What is the product of this step?
symbol =
mass number =
atomic number
Transcribed Image Text:The first four steps in the radioactive decay sequence of Po-218 are a, B, a, B. To write the reaction equations for this decay series, first determine the product of the first step. a decay of Po-218 gives: symbol = Pb mass number = 214 atomic number 82 Po undergoes four decay reactions: a, B, a, B. Step 1. *Po undergoes a decay to give Pb In the second step, Pb-214 undergoes B decay. What is the product of this step? 84 symbol = Bi mass number = 214 atomic number = 83 Po undergoes four decay reactions: a, B, a, B. Step 1. 218 Po undergoes a decay to give Pb Step 2. Pb undergoes B decay to give Bi 82 In the third step, Bi-214 undergoes a decay. What is the product of this step? symbol = mass number = atomic number
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