Plot the Shear and Bending moment diagrams for the following. Use Singularity Functions to Solve the problem y 400 lbf Hinge |A BAC R₂ R₁ 4 in 4 in 2 in 40 lbf/in 10 in D R3 ·X
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- The plane stress displacement field for the pure bending problem was given by u = - El v = (vy? + x² - P), where -1: | %85 || 2 100 Q1/ Two Forces Shown in Fig. (1) acts on the bracket, determine the effect of these two forces (using Parallelogram method). 150N F₁-200 N ||| Mech. eng. 1st atte - - ٩:٣٤ 71 ينة تكرير النفط والغاز | الدراسات الصباحية ندسة العمليات النفطية10 / 36 110% LQ23]( problem 지25's p37) Exepe20-원 At What angle &' must the (400N) force be applied in order to that the resultant `R of the two 400 N forces has a of (1000 N)? magnitude What will be the angle o between 700 N R and the horizontal (x-axis) ? Ane ∞ = 51.3° 0 = 18 19° P Type here to searchfind shear amd Binding momont okagrou 5KN/m 5m Tht 3m 707ASAPvio-Ou X 28523020?X-Blackboard-Expi 2/3 Ö 150% + A =651gq|4cRVazVmd0Uq2ZHfoUuaYHSBHXymA39vD1F0g%3D&X-Blackboard- 2) The ballistic pendulum is a simple device to measure projectile speed v by observing the maximum angle to which the box of sand with the embedded projectile swings. Calculate the pre-impact speed of the 40- gram projectile if the 16-kg box of sand swings up to a maximum angle of 0=23° after impact. 2 m 120dependent variables in hooks law experiment is stretching's force * false true5) Which statement is true about the friction factor in the Moody diagram (shown below). Moody Diagram 0.1 0.09 Transition Region 0.08 0.07 0.05 0.04 0,06 0.03 0.05 0.02 0.04 0.015 0.01 0.03 0.005 0.002 0.001 5x10-4 2x10-49 10-4 5x10-5 10-5 5x10-6 10-6 Friction Factor 12---- Laminar Flow 64 Material Concrete, coarse 0.25 0.025 Concrete, new smooth Drawn tubing 0.0025 Glass, Plastic Perspex 0.0025 Iron, cast 0.15 Sevens, old 3.0 0.1 Steel, mortar lined Steel, rusted 0.5 Stoel, structural or forgod 0.025 Water mains, old Friction Factor=AP. 1.0 Smooth Pipe 3000 10³ 10¹ 105 106 107 108 Reynolds Number, Re - Vd P a) The lines for different relative roughness in the turbulent regime correspond to Darcy-Weisbach model b) The lines for different relative roughness in the turbulent regime correspond to Nikuradse model c) The lines for different relative roughness in the turbulent regime correspond to Hazen-Williams model d) The lines for different relative roughness in the turbulent regime…5.2 Evaluate the Prandtl number from the following data: , .Consider the material Al-$456 It has the following physical ploperties Syleld = 230mPA %3D s-72GPA (modulos elasticity) Oultimate=315 mPA G- 28GPA Cmad vlus rigidity) Tuield =130 mPA Joltimate=185 mPA A Calculate Poisson's ratio B) If we have a following dimensions And Forces 3-0 block of Al-5456 with the Ex =800N X= Bcm Fy=1000N ) Is Our block Safes (consider only plane stes) Dset up the 3 eqetions to find the strains (Ex Ey E2) in each directian E Solve the 3exuations to find the Einal dimensions of our block1- Select the optimum choice for: high speed air craft skins material. Table 1: The properties of metallic materials E, GPa Max. use lemp, 'C | Density, Mg/cm' ay, MPa | Relative cost per unit sheet area Material 2.8 300 2 Aluminum alloy 200 69 200 7,8 350 350 700 Carbon steel Stainless steel 193 7.8 650 6 8.9 600 6 Nickel alloy Titanium alloy 207 1000 116 600 4.5 900 10 Table 2: Weighting factor Specific yield strength: Max, use temperature: Youngs modulus: 4 2The purpose of this problem is to show the relationship between material constants typically used in engineering practice. This is useful because you may often have access to measurements of or tabulated values of some constants (e.g., Young's modulus and Poisson's ratio) but need another constant (e.g., shear modulus) for a calculation. Use the expression Cijkl = µ(dildjk + dikdjl) + Ad¿jdkl to derive the following: (a) Young's modulus, E = µ(3X+2µ)/(X+μ), from the definition 11 = Ee11 in a unconfined (022 = 0,033 = 0) uniaxial tension test. (b) Poisson's ratio, v = \/(2(X + μ)), from the definition v = €22/11 in the same test as in (a). (c) Shear modulus, μ = G = 012/(2€12) = E/(2(1 + v)). Use the results to show that C can also be written Cijkl Ev/((1+v)(1 − 2v))dij§kl. = E/(2(1 + v))(duðjk + dikdjl) +SEE MORE QUESTIONS