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- why the expert here wrote -200 cos 75 when Σ Fx = 0 , I understand all steps but how he got - 200 cos 75 ( for the force ) (how the angle is 75 ) can you please clarify for me this point please ...... because I did not got the angle 75 dgree for 200 N force can you draw a diagrm for me please to see how 75 dgree links to 200 NHi please help with this question thank you I just can't seem to work it out even with the given formulas. Thanks! also, I have tried these but they seem to be incorrect, or maybe parts of the calculation may be incorrect since when I submit these all together and I can't really work out where I am going wrong: sigma 1 = 73.31 MPa theta 1 = 56.87 degrees sigma 2 = 18.68 MPa theta 2 = 146.875 degrees Tmax in plane = 27.315 MPa theta s = 101.87 degreesFind the axial stress (Subscript[\[Sigma], z]) and axial strain (Subscript[\[Epsilon], z]) for a thick-walled circular pipe subjected to an internal pressure Subscript[p, i] for the following three cases:a) the pipe is long and open (plane strain)b) the pipe is short and open (plane stress)c) the pipe is is closedExpress the above solutions in terms of the pressure Subscript[p, i], the the pipe inner and outer radii and the material constants.
- The state of stress at a point in an engine piston is given in the x-y-z coordinates by: 90 180 xx ху XZ [6]=0, |180 240 0 MPa ух yy yz 120 ZX zy Using the matrix transformation law, determine the state of stress at the same point for an element rotated about the x-axis (in the y-z plane) 60° clockwise from its original position. Calculate the stress invariants and write the characteristic equation for the original state of stress, Calculate the deviatoric invariants for the original state of stress, Calculate the principal stresses and the absolute maximum shear stress at the point. What are the stress invariants and the characteristic equation for the transformed state of stress, а. b. С. d. BREQ1 ( shown. * The stresses in a bracket were obtained from a 3D finite element analysis as (a) [A] = 0 (c) [σA] = [20 0 15 (e) [σA] = Which of the following stress tensors [A] correctly corresponds to the stress state at point A, as represented by the infinitesimal cube above. (All units in MPa.) 10 25 L15 25 -30] [-20 0 15 0 -10 -25 15 -25 -30 20 20 0 -15] 0 10 25 -15 25 -30] 30 15 25 25 Y [20 15 0 10 -25 -25 -30. (b) [A] = 15 LO (f) [A] = [20 (d) [A] = 0 L15 0 15 10 -25 -25 -30] OH O 0 [-20 -15] 0 -25 -15 -25 -30] -10dar Grubler's planar mcchanism to be onc. The mumber of degrees of freedom for below mentioned arrangement is 3- 651 14 (a) 0 18. (c) 2 (b) 1 ケ3 (d) 3
- Solve the following problems completely, and make a detailed solution. Use ONLY AREAMETHOD in finding the V-M Diagram. Please input the units in steps. Thankyou!Build the following part. Report the volume in mm^3. Assume all dimensions are in mm. A = 44 B = 78 40 20 10 Ø10 40 20 B 15 10 15 R20 30 10 T 20-Material 1- BRASS The below shown graph is drawn from the tabulated values of steel which we measured during the experiment of thermal (Diameter = 25mm) conductivity: (Consider the value of heater power (Q') and the area of cross section (A) of the material from the tabulated values) Power X-axis 1 unit =1 cm y-axis 1 unit = 10°C Temperature (°C) 50- Q' 1 2 3 4 5 6 7 8 (W) 14.65 79 77.4 76 50.1 46.5 42.4 36 34.5 : 20- 10- Distance X in cm 123 10 Material 2 - STEEL Calculate the following: Thermal conductivity of (Diameter = 25mm) steel Calculated Value quantities Power Difference in temperature (AT) C° (with sign) Difference in distance Temperature (°C) between test points (Ax) cm Slope from the graph °C/m (with sign) Q' 1 (W) 2 3 7 8 Thermal conductivity of steel ksb W/m°C 14.2 88.6 87.5 85 33.9 33.6 32.4
- I confused following this picture why (3.85-1.033)*10^-6Please find the Grashof classification and the Barker classification of the two four-bars: (NOTE: distances are in non-dimensional units. Can use inches or cm) P1) L1=d=4, theta1=0 degrees, L2=a=1.6, theta2=60 degrees, L3=b=5.5, L4=c=4.5 P1) L1=d=1, theta1=0 degrees, L2=a=1.25, theta2=120 degrees, L3=b=1.5, L4=c=2 Please also draw the four-bars to estimate the unknown angles theta3 and theta4.4ft Water 45° Fig. 5-23(a) The cylinder in the figure extends 2 ft into the paper. If the specific weight of water is 62 lb/ft°, Compute the; a) horizontal force acting on the cylinder [Select] b) vertical force acting on the cylinder [Select ] c) total hydrostatic force acting on the cylinder [ Select ]