Please provide the step-by-step and answer in the conversion format under the question and equation to help me better understand. Full depth on the process please ? A solution of tartaric acid (H.C HO.) with a known concentration of 0.155MH.CHO, is titrated with a 0.425 M NaOH solution. How many ml of NaOH arerequired to reach the second equivalence point with a starting volume of 70.0mL H,CHO, , according to the following balanced chemical equation:H.C,H,O, + 2 NaOH - Na C H,O̟ + 2 H,OSTARTING AMOUNTADD FACTORANSWERRESET*( )0.4255.11 x 1010000.051151.112.80.0217225.50.15570.010.001M NaOH LH,CHO. g H,CH,O mL NAOH MH.CHO g NaOHmol H,C,H,O,mol NaOHL NAOH mL H,C̟H̟O,

A solution of tartaric acid with a known concentration of 0.155 M are solution.

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Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter9: Acids, Bases, And Salts

Section: Chapter Questions

Problem 9.99E

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Please provide the step-by-step and answer in the conversion format under the question and equation to help me better understand. Full depth on the process please ?

A solution of tartaric acid (H.C HO.) with a known concentration of 0.155
MH.CHO, is titrated with a 0.425 M NaOH solution. How many ml of NaOH are
required to reach the second equivalence point with a starting volume of 70.0
mL H,CHO, , according to the following balanced chemical equation:
H.C,H,O, + 2 NaOH - Na C H,O̟ + 2 H,O
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
0.425
5.11 x 10
1000
0.0511
51.1
12.8
0.0217
2
25.5
0.155
70.0
1
0.001
M NaOH LH,CHO. g H,CH,O mL NAOH MH.CHO g NaOH
mol H,C,H,O,
mol NaOH
L NAOH mL H,C̟H̟O,

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