Please help and use the Heisler Charts provided to find the temperature to be able to solve the problem. Also show all steps on how answer was solved. This class is Heat Transfer. Thank you, will also rate the answer.         A horizontal copper plate (k= 374 W/m °C, a = 11.23×10-5 m 2 /s) 10 cm thick is initially uniform in temperature at 250 °C. The bottom surface of the plate is insulated. The top surface is suddenly exposed to a fluid stream at 80 °C. The convection heat transfer coefficient is 935 W/m2 °C. Use the Heisler charts (Figure 4-10) to find the temperature at the top surface (Tt) and then use the Heisler charts (Figure 4-7) to find the temperature at the bottom surface (Tb), and the middle of the plate (Tm) after 5 minutes?

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Please help and use the Heisler Charts provided to find the temperature to be able to solve the problem. Also show all steps on how answer was solved. This class is Heat Transfer. Thank you, will also rate the answer.         A horizontal copper plate (k= 374 W/m °C, a = 11.23×10-5 m 2 /s) 10 cm thick is initially uniform in temperature at 250 °C. The bottom surface of the plate is insulated. The top surface is suddenly exposed to a fluid stream at 80 °C. The convection heat transfer coefficient is 935 W/m2 °C. Use the Heisler charts (Figure 4-10) to find the temperature at the top surface (Tt) and then use the Heisler charts (Figure 4-7) to find the temperature at the bottom surface (Tb), and the middle of the plate (Tm) after 5 minutes?

Figure 4-7| Midplane temperature for an infinite plate of thickness 2L: (a) full scale.
1.0
0.7
90
100
0.5
0.4
i 80
F14
H 70
60
0.3
0.2
9
45
0.1
35
( 30
0.07
0.05
0.04
0.03
0.02
in xw
Pl 0.01
k/hL
0.007
0.005
0.004
0.003
0.002
400
500
600 700
300
0.001
0 1 2 3 4 6 8 10 12 14 16 18 20 22 24 26 28 30 40 50 60 70 80 90 100 110 130
150 200
at/L² = Fo
25
F0.06
= (To- T/(T;- T.)
Transcribed Image Text:Figure 4-7| Midplane temperature for an infinite plate of thickness 2L: (a) full scale. 1.0 0.7 90 100 0.5 0.4 i 80 F14 H 70 60 0.3 0.2 9 45 0.1 35 ( 30 0.07 0.05 0.04 0.03 0.02 in xw Pl 0.01 k/hL 0.007 0.005 0.004 0.003 0.002 400 500 600 700 300 0.001 0 1 2 3 4 6 8 10 12 14 16 18 20 22 24 26 28 30 40 50 60 70 80 90 100 110 130 150 200 at/L² = Fo 25 F0.06 = (To- T/(T;- T.)
Figure 4-10 | Temperature as a function of center temperature in an
infinite plate of thickness 2L, from Reference 2.
1.0
x/L = 0.2
0.9
-0.4.
0.8
0.7
0.6
-0.6
0.5
0.4
0.8
0.3
0.9
0.2
0.1
1.01
0.01 0.02 0.05 0.1 0.2 0.5 1.0
2 3 5 10 20 50 100
k
hL
Bi
0/0, = (T – T(To- T)
Transcribed Image Text:Figure 4-10 | Temperature as a function of center temperature in an infinite plate of thickness 2L, from Reference 2. 1.0 x/L = 0.2 0.9 -0.4. 0.8 0.7 0.6 -0.6 0.5 0.4 0.8 0.3 0.9 0.2 0.1 1.01 0.01 0.02 0.05 0.1 0.2 0.5 1.0 2 3 5 10 20 50 100 k hL Bi 0/0, = (T – T(To- T)
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