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Phosphoric acid is a triprotic acid (K, = 6.9 x 10- M, K2 = 6.2 x 10-* M, and K = 4.8 x 10-1 M). To find the pH of a buffer composed of H, PO, (aq) and HPO (aq), which pk, value would you use in the Henderson- Hasselbalch equation? O pK = 2.16 O pK2 = 7.21 O pKa = 12.32 Calculate the pH of a buffer solution obtained by dissolving 19.0 g KH, PO, (s) and 29.0 g Na, HPO, () in water and then diluting to 1.00 L. pH =

Phosphoric acid is a triprotic acid (K, = 6.9 x 10- M, K2 = 6.2 x 10-* M, and K = 4.8 x 10-1 M). To find the pH of a buffer composed of H, PO, (aq) and HPO (aq), which pk, value would you use in the Henderson- Hasselbalch equation? O pK = 2.16 O pK2 = 7.21 O pKa = 12.32 Calculate the pH of a buffer solution obtained by dissolving 19.0 g KH, PO, (s) and 29.0 g Na, HPO, () in water and then diluting to 1.00 L. pH =

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 28QRT: Calculate the pH change when 10.0 mL of 0.100-M NaOH is added to 90.0 mL pure water, and compare the...
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Phosphoric acid is a triprotic acid (K, = 6.9 x 10- M, K2 = 6.2 x 10-* M, and K = 4.8 x 10-1 M). To find the pH of a buffer composed of H, PO, (aq) and HPO (aq), which pk, value would you use in the Henderson- Hasselbalch equation? O pK = 2.16 O pK2 = 7.21 O pKa = 12.32 Calculate the pH of a buffer solution obtained by dissolving 19.0 g KH, PO, (s) and 29.0 g Na, HPO, (6) in water and then diluting to 1.00 L. pH =
Transcribed Image Text:Phosphoric acid is a triprotic acid (K, = 6.9 x 10- M, K2 = 6.2 x 10-* M, and K = 4.8 x 10-1 M). To find the pH of a buffer composed of H, PO, (aq) and HPO (aq), which pk, value would you use in the Henderson- Hasselbalch equation? O pK = 2.16 O pK2 = 7.21 O pKa = 12.32 Calculate the pH of a buffer solution obtained by dissolving 19.0 g KH, PO, (s) and 29.0 g Na, HPO, (6) in water and then diluting to 1.00 L. pH =
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