Perform the following set of operations and choose the alternative that expresses the result to the proper number of significant figures. (1.5 x 10-4 * 61.3) + 2.01 2.02 O 2.0192 2.019 O 2.0
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A: Given, Express the answers with the appropriate number of significant figures : (a). 14.3505 + 2.65…
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A: a) 14.5 + 0.023 = = 14.523 b) 13.265 -2.065 = = 11.2
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A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…
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A: Note:- Since you have asked multiple question, we will solve the first question for you. If you…
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A: To calculate the difference between two numbers.
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A: This can be solved by knowing the rules of significant figures.
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Q: significant figures. 1. Carry out the following mathematical operations, and give each result with…
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Q: otes: # of significant figures in the ans [NAOH] = 2.0 x 10³ M.
A: 6) [OH-] = 3.5×10-2 [H3O+] = 1.0×10-14/3.5×10-2 = 2.9×10-13 M 7) [NaOH] = 2.0×10-3 M As, NaOH is…
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A: The solution is as follows :
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Q: 2-Perform the following calculation and report the result to the correct number of significant…
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A: Some important properties : 1ax = a-x ax . ay =ax+y ( ax)y = ax.y axay = ax-y
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- Multiply both sides of the equation by the same expression: (Be sure that the answer field changes from light yellow to dark yellow before releasing your answer.) 1 1 *(-A) [A] [A]o Drag and drop your selection from the following list to complete the answer: -t 1 t = t 1 t x ktUse the References to access important values if needed for this question. Two-Step Algebra 1 1 bc + d In order to solve the equation above for b, you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: 1 + - = a +bc + - dUse the References to access important values if needed for this question. Two-Step Algebra a =b+ cd lne In order to solve the equation above for d, you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: -b ta =-bv +b+ cd Ine Step Two Multiply both sides of the equation by the same expression: x(a - b) = xcd Ine The resulting equation is: d = Submit
- The following linear plot is derived from a function of the form y = ae", where a and b are constants. 4.5 4 3.5 3 2.5 2 1.5 1 0.5 0 0.1 0.2 0.3 0.4 0.5 0.6 For the functiony = ae" from which the data points on the graph were derived, the numerical value of the constants are a = and b = A ujCalculate the kinetic energy of a ×9.41012kg comet moving at a speed of 39.0kms .Round your answer to 2 significant digits.The following linear plot is derived from a function of the form Y = ae", where a and b are constants. 7 6 5 4 2 1 0 0.1 0.2 0.3 0.4 0.5 0.6 For the function y = ae' bx from which the data points on the graph were derived, the numerical value of the constants are a = and b = In y
- What is the boiling point of the unknown substance Xin K(Kelvin)? X(t) = X(g) AH-(kJ mol1) S°J mol1K1) X(g) -82.0 238 | X({) | -101 144 Express your answer in decimal notation rounded to three significant figures.Two-Step Algebra a = -bc+d Use the References to access important values if needed for this question. In order to solve the equation above for c, you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: +a = -bc+dCalculate the kinetic energy of a 2.1 X 10^14 kg comet moving at a speed of 17.0km/s Round your answer to 2 significant digits.
- Powers of 10 - multiply Solve for the variables below. a. 769.17× 10² 7.6917 p= b. 881.73× 10¯4=j j=1s²25²2p°3s²3psmoke particles in air typically have masses of the order of 10^-16 kg. The rapid, irregular motions of these particles caused by collisions with air molecules can be observed with a microscope. Assume a particular type of smoke particle has a mass of 3.00 x10^-16 kg and is in a room with a temperature of 300 K. a) if instead you were considering a hydrogen gas molecule (m= 3.34x10^-26 kg) at 300 K, would the average translational kinetic energy be larger than, smaller than or equal to that of the smoke particle? b) would the rms speed of the hydrogen atom be larger than, smaller than, or equal to that of the smoke particle?