Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(1). Calculate AHrxn for the combustion of 5.00 mol of B5Hg. AH°F[B203(s)] =-1,273.5 kJ/mol AH°f[B5H9(s)] = 73.2 kJ/mol AH°f[H2O(1)] = -285.8 kJ/mol Multiple Choice - 8,790 kJ - 45,400 kJ 45,400 kJ - 22,700 kJ

Chemistry by OpenStax (2015-05-04)
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Chapter5: Thermochemistry
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- 8,790 kJ
- 45,400 kJ
45,400 kJ
- 22,700 kJ
- 9,090 kJ
Transcribed Image Text:Multiple Choice - 8,790 kJ - 45,400 kJ 45,400 kJ - 22,700 kJ - 9,090 kJ
Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(1). Calculate AHrxn for the combustion of 5.00 mol of B5H9.
AH°F[B2O3(s)] =-1,273.5 kJ/mol
AH°f[B5H9(s)] = 73.2 kJ/mol
AH°f[H2O(1)] = -285.8 kJ/mol
Multiple Choice
- 8,790 kJ
- 45,400 kJ
45,400 kJ
- 22,700 kJ
Transcribed Image Text:Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(1). Calculate AHrxn for the combustion of 5.00 mol of B5H9. AH°F[B2O3(s)] =-1,273.5 kJ/mol AH°f[B5H9(s)] = 73.2 kJ/mol AH°f[H2O(1)] = -285.8 kJ/mol Multiple Choice - 8,790 kJ - 45,400 kJ 45,400 kJ - 22,700 kJ
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